1) (4x-1)(x-3) = (x-3)(5x+2) 2) (x+3)(x-5)+(x+3)(3x-4)=0 3) (x+6)(3x-1) + x+6=0 4) (x+4)(5x+9) –x

Bởi

1) (4x-1)(x-3) = (x-3)(5x+2) 2) (x+3)(x-5)+(x+3)(3x-4)=0
3) (x+6)(3x-1) + x+6=0 4) (x+4)(5x+9) –x – 4= 0
5) (1 –x )(5x+3) = (3x -7)(x-1) 6) 2x(2x-3) = (3 – 2x)(2-5x)

0 bình luận về “1) (4x-1)(x-3) = (x-3)(5x+2) 2) (x+3)(x-5)+(x+3)(3x-4)=0 3) (x+6)(3x-1) + x+6=0 4) (x+4)(5x+9) –x”

  1. `(4x-1)(x-3) = (x-3)(5x+2)`

    `<=>4x^2-12x-x+3=5x^2+2x-15x-6`

    `<=>4x^2+3=5x^2-6`

    `<=>x=+-3`

    `(x+3)(x-5)+(x+3)(3x-4)=0`

    `<=>(x+3)(2x-11)=0`

    `<=>x=-3` hoặc `x=11/2`

    `(x+6)(3x-1) + x+6=0`

    `<=>(x+6)(3x-1+1)=0`

    `<=>x=-6` hoặc `x=0`

    `(x+4)(5x+9) –x – 4= 0`

    `<=>(x+4)(5x-8)=0`

    `<=>x=-4` hoặc `x=8/5`

    `(1 –x )(5x+3) = (3x -7)(x-1)`

    `<=>5x+3-5x^2-3x=3x^2-3x-7x+7`

    `<=>4(3x-1-2x^2)=0`

    `<=>x=1/2` hoặc `x=1`

    `2x(2x-3) = (3 – 2x)(2-5x)`

    `<=>4x^2-6x=6-15x-4x+10x^2`

    `<=>6x^2-13x+6=0`

    `<=>x=2/3` hoặc `x=3/2`

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