1) (x-5)(x-1)=(x-1)(x-2) 2) 6(x-3)(x-4)-6x(x-2)=4 3) -3(x+3)(x-4)+(x-1)(x+1)=10 19/09/2021 Bởi Vivian 1) (x-5)(x-1)=(x-1)(x-2) 2) 6(x-3)(x-4)-6x(x-2)=4 3) -3(x+3)(x-4)+(x-1)(x+1)=10
`1)` `(x-5)(x-1)=(x-1)(x-2)` `⇔(x-5)(x-1)-(x-1)(x-2)=0` `⇔(x-1)(x-5-x+2)=0` `⇔-3(x-1)=0` `⇔x-1=0` `⇔x=1` `2)` `6(x-3)(x-4)-6x(x-2)=4` `⇔6(x^2-4x-3x+12)-6x^2+12x-4=0` `⇔6x^2-24x-18x+72-6x^2+12x-4=0` `⇔-30x=-68` `⇔x=34/15` `3)` `-(x+3)(x-4)+(x-1)(x+1)=10` `⇔-(x^2-4x+3x-12)+x^2-1=10` `⇔-x^2+4x-3x+12+x^2-1=10` `⇔x+11=0` `⇔x=-11` Bình luận
Đáp án:
Giải thích các bước giải:
`1)` `(x-5)(x-1)=(x-1)(x-2)`
`⇔(x-5)(x-1)-(x-1)(x-2)=0`
`⇔(x-1)(x-5-x+2)=0`
`⇔-3(x-1)=0`
`⇔x-1=0`
`⇔x=1`
`2)` `6(x-3)(x-4)-6x(x-2)=4`
`⇔6(x^2-4x-3x+12)-6x^2+12x-4=0`
`⇔6x^2-24x-18x+72-6x^2+12x-4=0`
`⇔-30x=-68`
`⇔x=34/15`
`3)` `-(x+3)(x-4)+(x-1)(x+1)=10`
`⇔-(x^2-4x+3x-12)+x^2-1=10`
`⇔-x^2+4x-3x+12+x^2-1=10`
`⇔x+11=0`
`⇔x=-11`