1.(6x + 1)^2 + (6x – 1)^2 – 2(1 + 6x)(6x – 1) 2. 3(2^2 + 1)(2^4 + 1)(2^8 + 1)(2^16 + 1) 12/10/2021 Bởi Quinn 1.(6x + 1)^2 + (6x – 1)^2 – 2(1 + 6x)(6x – 1) 2. 3(2^2 + 1)(2^4 + 1)(2^8 + 1)(2^16 + 1)
`1)` ` (6x+1)^2 +(6x-1)^2 -2(1+6x)(6x-1)` ` = [ (6x+1) – (6x-1)]^2` ` = ( 6x +1 -6x +1)^2` ` = 2^2 = 4` `2)` ` 3(2^2+1)(2^4+1)(2^8+1)(2^(16)+1)` ` = (2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^(16)+1)` ` = (2^4 -1)(2^4+1)(2^8+1)(2^(16)+1)` ` = (2^8-1)(2^8+1)(2^(16)+1)` ` = (2^(16)-1)(2^(16)+1)` ` = 2^(32) -1` Bình luận
1/ $(6x+1)²+(6x-1)²-2(1+6x)(6x-1)$ $=(6x+1-6x+1)²=2²=4$ 2/ $3(2^2+1)(2^4+1)(2^8+1)(2^{16}+1)$ $=(2^1-1)(2^2+1)(2^4+1)(2^8+1)(2^{16}+1)$ $=(2^4-1)(2^4+1)(2^8+1)(2^{16}+1)$ $=(2^8-1)(2^8+1)(2^{16}+1)$ $=(2^{16}-1)(2^{16}+1)=2^{32}-1$ Bình luận
`1)`
` (6x+1)^2 +(6x-1)^2 -2(1+6x)(6x-1)`
` = [ (6x+1) – (6x-1)]^2`
` = ( 6x +1 -6x +1)^2`
` = 2^2 = 4`
`2)`
` 3(2^2+1)(2^4+1)(2^8+1)(2^(16)+1)`
` = (2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^(16)+1)`
` = (2^4 -1)(2^4+1)(2^8+1)(2^(16)+1)`
` = (2^8-1)(2^8+1)(2^(16)+1)`
` = (2^(16)-1)(2^(16)+1)`
` = 2^(32) -1`
1/ $(6x+1)²+(6x-1)²-2(1+6x)(6x-1)$
$=(6x+1-6x+1)²=2²=4$
2/ $3(2^2+1)(2^4+1)(2^8+1)(2^{16}+1)$
$=(2^1-1)(2^2+1)(2^4+1)(2^8+1)(2^{16}+1)$
$=(2^4-1)(2^4+1)(2^8+1)(2^{16}+1)$
$=(2^8-1)(2^8+1)(2^{16}+1)$
$=(2^{16}-1)(2^{16}+1)=2^{32}-1$