`(x+1)/9=25/(1+x)` `3/4=5/(x+2)` `81/(3^x)=3` 27/11/2021 Bởi Caroline `(x+1)/9=25/(1+x)` `3/4=5/(x+2)` `81/(3^x)=3`
Đáp án: c) x=3 Giải thích các bước giải: \(\begin{array}{l}a)DK:x \ne – 1\\\dfrac{{x + 1}}{9} = \dfrac{{25}}{{x + 1}}\\ \to {\left( {x + 1} \right)^2} = 9.25\\ \to \left| {x + 1} \right| = 15\\ \to \left[ \begin{array}{l}x + 1 = 15\\x + 1 = – 15\end{array} \right.\\ \to \left[ \begin{array}{l}x = 14\\x = – 16\end{array} \right.\\b)DK:x \ne – 2\\\dfrac{3}{4} = \dfrac{5}{{x + 2}}\\ \to 3x + 6 = 20\\ \to 3x = 14\\ \to x = \dfrac{{14}}{3}\\c)\dfrac{{81}}{{{3^x}}} = 3\\ \to {3^x} = 27\\ \to {3^x} = {3^3}\\ \to x = 3\end{array}\) Bình luận
Đáp án:
c) x=3
Giải thích các bước giải:
\(\begin{array}{l}
a)DK:x \ne – 1\\
\dfrac{{x + 1}}{9} = \dfrac{{25}}{{x + 1}}\\
\to {\left( {x + 1} \right)^2} = 9.25\\
\to \left| {x + 1} \right| = 15\\
\to \left[ \begin{array}{l}
x + 1 = 15\\
x + 1 = – 15
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 14\\
x = – 16
\end{array} \right.\\
b)DK:x \ne – 2\\
\dfrac{3}{4} = \dfrac{5}{{x + 2}}\\
\to 3x + 6 = 20\\
\to 3x = 14\\
\to x = \dfrac{{14}}{3}\\
c)\dfrac{{81}}{{{3^x}}} = 3\\
\to {3^x} = 27\\
\to {3^x} = {3^3}\\
\to x = 3
\end{array}\)