(x+1)/99 + (x+3)/97 + (x+5)/95 = (x+7)/93 + (x+9)/91 + (x+11)/89

(x+1)/99 + (x+3)/97 + (x+5)/95 = (x+7)/93 + (x+9)/91 + (x+11)/89

0 bình luận về “(x+1)/99 + (x+3)/97 + (x+5)/95 = (x+7)/93 + (x+9)/91 + (x+11)/89”

  1. $\frac{x+1}{99}+$ $\frac{x+3}{97}+$ $\frac{x+5}{95}=$ $\frac{x+7}{93}+$ $\frac{x+9}{91}+$ $\frac{x+11}{89}$

    <=>$(\frac{x+1}{99}+1)+$ $(\frac{x+3}{97}+1)+($ $(\frac{x+5}{95}+1)-$ $(\frac{x+7}{93}+1)-($ $\frac{x+9}{91}+1)-($ $\frac{x+11}{89}+1)=0$ <=>$\frac{x+100}{99}+$ $\frac{x+100}{97}+$ $\frac{x+100}{95}-$ $\frac{x+100}{93}-$ $\frac{x+100}{91}-$ $\frac{x+100}{89}=0$

    <=>$(x+100)($$\frac{1}{99}+$ $\frac{1}{97}+$ $\frac{1}{95}-$ $\frac{1}{93}-$ $\frac{1}{91}-$ $\frac{1}{89})=0$

    <=>$x+100=0$

    <=>$x=-100$

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  2. Đáp án:x=-100

     

    Giải thích các bước giải:

    (x+1)/99 + (x+3)/97 + (x+5)/95 = (x+7)/93 + (x+9)/91 + (x+11)/89

    ⇔((x+1)/99 +1)+((x+3)/97 +1)+((x+5)/95+1)=((x+7)/93+1)+((x+9)/91+1)+((x+11)/89+1)

    ⇔(x+100)/99 + (x+100)/97 + (x+100)/95 = (x+100)/93 + (x+100)/91 + (x+100)/89

    ⇔(x+100) (1/99+1/97+1/95-1/93-1/91-1/89)=0

    ⇔x+100=0

    ⇔x=-100

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