1/ a. ( 1-3/5)^5 + | -7/23 | + ( -4/25 ) b. ( -31/37 )^5 × ( 37/62 )^5 2/ tìm x a. ( x – 3/5 )^2 =4 b. 2^x + 2^x+3 =144

0 bình luận về “1/ a. ( 1-3/5)^5 + | -7/23 | + ( -4/25 ) b. ( -31/37 )^5 × ( 37/62 )^5 2/ tìm x a. ( x – 3/5 )^2 =4 b. 2^x + 2^x+3 =144”

1. 1.

   a.=2/5^5+7/23+(-4/25)

    =2/5^2×2/5^3+7/23+(-4/25)

    =4/25×8/125+7/23+(-4/25)

    ={4/25+(-4/25}×8/125+7/23

    =0×8/125+7/23

    =0+7/23

    =7/23

   2.

   a.(x-3/5)^2=4

   (x-3/5)^2=2^2

   x-3/5=2

   x=2+3/5

   x=13/5

   Vậy…

   b.2^x+2^x+3=144

   =>2^x×1+2^x×2^3=144

   =>2^x×(1+2^3)=144

   =>2^x×9=144

   =>2^x=144:9=16

   =>x=4

   Vậy ….

   Câu bé bài 2 mk chx làm nha

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2. 1.

   a.=2/5^5+7/23+(-4/25)

    =2/5^2×2/5^3+7/23+(-4/25)

    =4/25×8/125+7/23+(-4/25)

    ={4/25+(-4/25}×8/125+7/23

    =0×8/125+7/23

    =0+7/23

    =7/23

   2.

   a.(x-3/5)^2=4

   (x-3/5)^2=2^2

   x-3/5=2

   x=2+3/5

   x=13/5

   Vậy:x=13/5

   b.2^x+2^x+3=144

   =>2^x×1+2^x×2^3=144

   =>2^x×(1+2^3)=144

   =>2^x×9=144

   =>2^x=144:9=16

   =>x=4

   Vây:x=4

   CHO XIN HAY NHẤT NHA

    

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