1/ a. ( 1-3/5)^5 + | -7/23 | + ( -4/25 ) b. ( -31/37 )^5 × ( 37/62 )^5 2/ tìm x a. ( x – 3/5 )^2 =4 b. 2^x + 2^x+3 =144

1.

a.=2/5^5+7/23+(-4/25)

 =2/5^2×2/5^3+7/23+(-4/25)

 =4/25×8/125+7/23+(-4/25)

 ={4/25+(-4/25}×8/125+7/23

 =0×8/125+7/23

 =0+7/23

 =7/23

2.

a.(x-3/5)^2=4

(x-3/5)^2=2^2

x-3/5=2

x=2+3/5

x=13/5

Vậy…

b.2^x+2^x+3=144

=>2^x×1+2^x×2^3=144

=>2^x×(1+2^3)=144

=>2^x×9=144

=>2^x=144:9=16

=>x=4

Vậy ….

Câu bé bài 2 mk chx làm nha