1.rút gọn $\frac{1-cos2x}{sin2x}$ p= cos2x + 2 m ∈ Δ $\left \{ {{x= -2 + t} \atop {y = 3 +t}} \right.$ cách a = √5 25/09/2021 Bởi Mary 1.rút gọn $\frac{1-cos2x}{sin2x}$ p= cos2x + 2 m ∈ Δ $\left \{ {{x= -2 + t} \atop {y = 3 +t}} \right.$ cách a = √5
Đáp án: $\begin{array}{l}A = \dfrac{{1 – \cos 2x}}{{\sin 2x}}\\ = \dfrac{{2{{\sin }^2}x}}{{2.\sin x.\cos x}}\\ = \dfrac{{\sin x}}{{\cos x}}\\ = \tan x\\P = \cos 2x + 2\\ = 2{\cos ^2}x – 1 + 2\\ = 2.{\cos ^2}x + 1\end{array}$ Bình luận
Đáp án:
$\begin{array}{l}
A = \dfrac{{1 – \cos 2x}}{{\sin 2x}}\\
= \dfrac{{2{{\sin }^2}x}}{{2.\sin x.\cos x}}\\
= \dfrac{{\sin x}}{{\cos x}}\\
= \tan x\\
P = \cos 2x + 2\\
= 2{\cos ^2}x – 1 + 2\\
= 2.{\cos ^2}x + 1
\end{array}$