1,tìm x
2.3 mũ x=162
2 mũ x – 15=17
(7 mũx -11)mũ 3 = 5 mũ 2+200
x mũ 10=x
1,tìm x 2.3 mũ x=162 2 mũ x – 15=17 (7 mũx -11)mũ 3 = 5 mũ 2+200 x mũ 10=x
By Quinn
By Quinn
1,tìm x
2.3 mũ x=162
2 mũ x – 15=17
(7 mũx -11)mũ 3 = 5 mũ 2+200
x mũ 10=x
a) 3^x=162
2.3∧X=2.3∧4
⇒x=4
b)2∧x -15=17
2∧x=32
2∧X=2∧5
⇒x=5
(7x-11)∧3=5∧2+200
(7x-11)∧3=25.32+200
(7x-11)∧3=1000
(7x-11)∧3=10∧3
7x-11=10
7x=21
x=3
x∧10=x
⇒x∧10-x=0
⇒x.(x∧9-1)=0
TH1:⇒x=0
TH2:⇒x∧9-1=0⇒x=1
Vậy x=0 hoặc x=1
Giải thích các bước giải:
`2.3 ^ x=162`
`=>3^x=162:2`
`=>3^x=81`
`=>3^x=3^4`
`=>x=4`
`2 ^ x – 15=17`
`=>2^x=17+15`
`=>2^x=32`
`=>2^x=2^5`
`=>x=5`
`(7.x-11)^3=5^2. 2^5+200`
`=>(7.x – 11)^3=25 . 32+200`
`=>(7.x – 11)^3=800+200`
`=>(7.x – 11)^3=1000`
`=>(7.x – 11)^3=10^3`
`=>7.x – 11=10`
`=>7.x = 10+11`
`=>7.x=21`
`=>x=21:7`
`=>x=3`
`x^10=x`
`=>x^10-x=0`
`=>x^9 . x-x.1=0`
`=>x.(x^9 -1)=0`
`=>`\(\left[ \begin{array}{l}x=0\\x^9 – 1=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=0\\x^9=0+1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=0\\x^9=1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=0\\x^9=1^9\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=0\\x=1\end{array} \right.\)