1. Tìm lim [(n^2 – 2) / (5n + 3n^2)] 2. Tìm lim [(n^2 – 2n) / (5n + 3n^2)] 05/11/2021 Bởi Reese 1. Tìm lim [(n^2 – 2) / (5n + 3n^2)] 2. Tìm lim [(n^2 – 2n) / (5n + 3n^2)]
1. $\lim\dfrac{n^2-2}{5n+3n^2}$ $=\lim\dfrac{1-\dfrac{2}{n^2}}{\dfrac{5}{n}+3}$ $=\dfrac{1}{3}$ 2. $\lim\dfrac{n^2-2n}{5n+3n^2}$ $=\lim\dfrac{1-\dfrac{2}{n}}{\dfrac{5}{n}+3}$ $=\dfrac{1}{3}$ Bình luận
$1)$ ` lim {n^2 – 2} / {5n + 3n^2}` `=lim {n^2 (1-2/{n^2})}/{n^2 (5/n+3)}` `=lim {1-2/{n^2}}/{5/n +3}={1+0}/{0+3}=1/3` $\\$ $2)$ `lim {n^2 – 2n} / {5n + 3n^2}` `=lim {n^2 (1-2/n)}/{n^2 (5/n+3)}` `=lim {1-2/n}/{5/n +3}={1+0}/{0+3}=1/3` Bình luận
1.
$\lim\dfrac{n^2-2}{5n+3n^2}$
$=\lim\dfrac{1-\dfrac{2}{n^2}}{\dfrac{5}{n}+3}$
$=\dfrac{1}{3}$
2.
$\lim\dfrac{n^2-2n}{5n+3n^2}$
$=\lim\dfrac{1-\dfrac{2}{n}}{\dfrac{5}{n}+3}$
$=\dfrac{1}{3}$
$1)$ ` lim {n^2 – 2} / {5n + 3n^2}`
`=lim {n^2 (1-2/{n^2})}/{n^2 (5/n+3)}`
`=lim {1-2/{n^2}}/{5/n +3}={1+0}/{0+3}=1/3`
$\\$
$2)$ `lim {n^2 – 2n} / {5n + 3n^2}`
`=lim {n^2 (1-2/n)}/{n^2 (5/n+3)}`
`=lim {1-2/n}/{5/n +3}={1+0}/{0+3}=1/3`