1. tính : 68mod 5+4 99 div 11-3 2. ax^2+bx+2c 2x+y/5-x^2+y (x-y)/(2*x) ((1+x)*(1+x))/2 01/08/2021 Bởi Ximena 1. tính : 68mod 5+4 99 div 11-3 2. ax^2+bx+2c 2x+y/5-x^2+y (x-y)/(2*x) ((1+x)*(1+x))/2
1. Tính: a. (68 mod 5) + 4 `= 3 + 4 = 7` b. (99 div 11) – 3 `= 9 – 3 = 6` 2. `ax^2 + bx +2c` → a*x*x+b*x+2*c `2x+y/5-x^2+y` → 2*x+y/5-x*x+y (x-y)/(2*x) → `{x-y}/{2x}` ((1+x)*(1+x))/2 → `{(1+x)^2}/2` Bình luận
a, `68 mod5+4=3+4=7` b, `99div11-3=9-3=6` 2) `=ax^2+bx+2c` `=2x+y/5-x^2+y` `=(x-y)/2x` `=(1+x)^2/2` Bình luận
1. Tính:
a. (68 mod 5) + 4 `= 3 + 4 = 7`
b. (99 div 11) – 3 `= 9 – 3 = 6`
2.
`ax^2 + bx +2c` → a*x*x+b*x+2*c
`2x+y/5-x^2+y` → 2*x+y/5-x*x+y
(x-y)/(2*x) → `{x-y}/{2x}`
((1+x)*(1+x))/2 → `{(1+x)^2}/2`
a, `68 mod5+4=3+4=7`
b, `99div11-3=9-3=6`
2)
`=ax^2+bx+2c`
`=2x+y/5-x^2+y`
`=(x-y)/2x`
`=(1+x)^2/2`