1,Tính a, ($\frac{-1}{4}$+ $\frac{7}{33}$ -$\frac{5}{3}$) – ($\frac{-5}{12}$ +$\frac{6}{11}$ – $\frac{48}{49}$) b, $\frac{3}{2}$ + $\frac{5}{4}$ +$\fr

Bởi

1,Tính
a, ($\frac{-1}{4}$+ $\frac{7}{33}$ -$\frac{5}{3}$) – ($\frac{-5}{12}$ +$\frac{6}{11}$ – $\frac{48}{49}$)
b, $\frac{3}{2}$ + $\frac{5}{4}$ +$\frac{9}{8}$ + $\frac{17}{16}$ + $\frac{33}{32}$ + $\frac{65}{64}$ – 7

0 bình luận về “1,Tính a, ($\frac{-1}{4}$+ $\frac{7}{33}$ -$\frac{5}{3}$) – ($\frac{-5}{12}$ +$\frac{6}{11}$ – $\frac{48}{49}$) b, $\frac{3}{2}$ + $\frac{5}{4}$ +$\fr”

  2. Bạn tham khảo nhé.
                                         Bài làm

    a) ($\frac{-1}{4}$ + $\frac{7}{33}$  – $\frac{5}{3}$ ) – ($\frac{-5}{12}$ + $\frac{6}{11}$  – $\frac{48}{49}$)
    = ($\frac{-5}{132}$ – $\frac{5}{3}$) – ($\frac{17}{132}$ – $\frac{48}{49}$)
    = $\frac{-75}{44}$ – $\frac{-5503}{6468}$
    = $\frac{-251}{294}$
    b) $\frac{3}{2}$ + $\frac{5}{4}$ + $\frac{9}{8}$ + $\frac{17}{16}$ + $\frac{33}{32}$ + $\frac{65}{64}$ – 7
    = $\frac{11}{4}$ + $\frac{9}{8}$ + $\frac{17}{16}$ + $\frac{33}{32}$ + $\frac{65}{64}$ – 7
    = $\frac{31}{8}$ + $\frac{17}{16}$ + $\frac{33}{32}$ + $\frac{65}{64}$ – 7
    = $\frac{79}{16}$ + $\frac{33}{32}$ + $\frac{65}{64}$ – 7
    = $\frac{191}{32}$ + $\frac{65}{64}$ – 7
    = $\frac{447}{64}$ – 7
    = $\frac{-1}{64}$
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