1)Tính nhanh (123-145)-(23+55) (236-185)-(-85+36) 142-(150-249)-(249+42) 2) Tìm x 1)(x+3)^2=81 2)(2x-1)^4=625 3)(x-5)^4=(x-5)^6

1)Tính nhanh
(123-145)-(23+55)
(236-185)-(-85+36)
142-(150-249)-(249+42)
2) Tìm x
1)(x+3)^2=81
2)(2x-1)^4=625
3)(x-5)^4=(x-5)^6

0 bình luận về “1)Tính nhanh (123-145)-(23+55) (236-185)-(-85+36) 142-(150-249)-(249+42) 2) Tìm x 1)(x+3)^2=81 2)(2x-1)^4=625 3)(x-5)^4=(x-5)^6”

  1. `1)`

    `1)(123-145)-(23+55)`

    `=123-145-23-55`

    `=(123-23)+(-145-55)`

    `=100-200=-100`

    `2)(236-185)-(-85+36)`

    `=236-185+85-36`

    `=(236-36)+(-185+85)`

    `=200-100=100`

    `3)142-(150-249)-(249+42)`

    `=142-150+249-249-42`

    `=(142-42)-150+(249-249)`

    `=100-150=-50`

    `2)`

    ` 1)(x+3)^2=81`

    ` (x+3)^2=9^2`

    ` x+3=9`

    ` x=6`

    `2)(2x-1)^4=625`

    `(2x-1)^4=5^4`

    `2x-1=5`

    `2x=6`

    `x=3`

    `3)(x-5)^4=(x-5)^6`

    `(x-5)^4-(x-5)^6=0`

    `(x-5)^4[1-(x-5)^2]=0`

    `<=>`\(\left[ \begin{array}{l}(x-5)^4=0\\1-(x-5)^2=0\end{array} \right.\)

    `<=>`\(\left[ \begin{array}{l}x-5=0\\(x-5)^2=1\end{array} \right.\)

    `<=>`\(\left[ \begin{array}{l}x=5\\\left[ \begin{array}{l}x-5=1\\x-5=-1\end{array} \right.⇔\left[ \begin{array}{l}x=6\\x=4\end{array} \right.\end{array} \right.\)

    `=>x={4;5;6}`

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  2. 1)Tính nhanh

    (123-145)-(23+55)

    = 123-145-23+55

    =(123-123)-(145+55)

    =100-200

    =100+(-200)

    =-100

    (236-185)-(-85+36)

    =236-185+85-36

    =(236-36)+(-185-85)

    =200-100

    =100

    142-(150-249)-(249+42)

    =142-150+249-249-42

    =(142-42)-150+(249-249)

    =100-150+0

    =100-150

    =-50

    2) Tìm x

    1)(x+3)²=81

    ⇒(x+3)²=9²

    ⇒x+3    =9

    ⇒x         =9-3

    ⇒x         =6

    Vậy x=6

    2)(2x-1)^4=625

    ⇒(2x-1)^4=5^4

    ⇒(2x-1)     =5

    ⇒2x           =5-1

    ⇒2x           =4

    x             =4:2

    ⇒x             =2

    Vậy x=2

    3)(x-5)^4=(x-5)^6

    ⇒(x-5)^6-(x-5)^4=0

    ⇒(x-5)^4.[(x-5)²-1]=0

    ⇒(x-5)^4=0 hoặc [(x-5)²-1]=0

    TH1:

    (x-5)^4=0

    ⇒x-5=0

    ⇒x    =5

    TH2:

    [(x-5)²-1]=0

    ⇒(x-5)²  =1

    ⇒(x-5)²  =1 hoặc (x-5)²  =-1

    ⇒x∈{6;4}

    Vậy x∈{4;5;6}

    #Chúc bạn học tốt!

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