1. Tính tổng
$a)\frac{2}{1.3}+$ $\frac{2}{3.5}+$ $\frac{2}{5.7}+…+$ $\frac{2}{99.101}$
$b)\frac{5}{1.3}+$ $\frac{5}{3.5}+$ $\frac{5}{5.7}+…+$ $\frac{5}{99.101}$
1. Tính tổng
$a)\frac{2}{1.3}+$ $\frac{2}{3.5}+$ $\frac{2}{5.7}+…+$ $\frac{2}{99.101}$
$b)\frac{5}{1.3}+$ $\frac{5}{3.5}+$ $\frac{5}{5.7}+…+$ $\frac{5}{99.101}$
Đáp án:
Giải thích các bước giải:
a) 1/1 -1/3 +1/3 -1/5 +1/5 -1/7 +…..+ 1/99 -1/101
=1-1/101=100/101
b) 3( 1/1 -1/3 +1/3 -1/5 +1/5 _1/7 +….+1/99-1/101
=3( 1/1- 1/101) = 300/ 101
`a,2/(1.3)+2/(3.5)+2/(5.7)+…+2/(99.101)`
`=2(1/(1.3)+1/(3.5)+1/(5.7)+…+1/(99.101))`
`=1-1/3+1/3-1/5+1/5-1/7+…+1/99-1/101`
`=1-1/101`
`=100/101`
`b,5/(1.3)+5/(3.5)+5/(5.7)+…+5/(99.101)`
`=5/2(1-1/3+1/3-1/5+1/5-1/7+…+1/99-1/101)`
`=5/2(1-101)`
`=250/101`