1.viết pthh minh hoạ cho t/c hh của oxi
1,p(v)+o2=> 6,al(iii)+o2=>
2,c(iv)+o2=> 7,ch4+o2=>
3,s(iv)+o2=> 8,Fes2+o2=>
4,fe(iii)+o2=> 9,C4h10+o2=>
5,cu(ii)+o2=> 10,na(i)+o2=>
$4P+5O_2\overset{t^o}{\longrightarrow}2P_2O_5$
$C+O_2\overset{t^o}{\longrightarrow}CO_2$
$S+O_2\overset{t^o}{\longrightarrow}SO_2$
$3Fe+2O_2\overset{t^o}{\longrightarrow}Fe3O_4$
$2Cu+O_2\overset{t^o}{\longrightarrow}2CuO$
$4Al+3O_2\overset{t^o}{\longrightarrow}2Al_2O_3$
$CH_4+2O_2\overset{t^o}{\longrightarrow}CO_2+2H_2O$
$4FeS_2+11O_2\overset{t^o}{\longrightarrow}2Fe_2O_3+8SO_2$
$2C_4H_{10}+13O_2\overset{t^o}{\longrightarrow}8CO_2+10H_2O$
$4Na+O_2\overset{t^o}{\longrightarrow}Na_2O$
Đáp án:
Câu 1:
$1/ 4P + 5O2 -to-> 2P2O5$
$2/ C + O2 -to-> CO2$
$3/ S + O2 -to-> SO2$
$4/ 3Fe + 2O2 -to-> Fe3O4$
$5/ 2Cu + O2 -to-> 2CuO$
$6/ 4Al + 3O2 -to-> 2Al2O3$
$7/ CH4 + 2O2 -to-> CO2 + 2H2O$
$8/ 4FeS2 + 11O2 -to-> 2Fe2O3 + 8SO2$
$9/ 2C4H10 + 13O2 -to-> 8CO2 + 10H2O$
$10/ 4Na + O2 -to-> 2Na2O$