Toán 1, y= 5tan4x – 3x 2, y= tanx – 3cotx 3, y = (x^2 + 3)tanx + 1/x 02/08/2021 By Maria 1, y= 5tan4x – 3x 2, y= tanx – 3cotx 3, y = (x^2 + 3)tanx + 1/x
1. Để $\tan4x$ xác định: ĐK: $\cos 4x\ne 0$ $\Leftrightarrow 4x\ne \dfrac{\pi}{2}+k\pi$ $\Leftrightarrow x\ne\dfrac{\pi}{8}+\dfrac{k\pi}{4}$ 2. Để $\tan x$, $\cot x$ xác định: ĐK: $\cos x\ne 0; \sin x\ne 0$ $\Leftrightarrow \sin2x\ne 0$ $\Leftrightarrow 2x\ne k\pi$ $\Leftrightarrow x\ne \dfrac{k\pi}{2}$ 3. ĐK: $\cos x\ne 0; x\ne 0$ $\Leftrightarrow x\ne \dfrac{\pi}{2}+k\pi; x\ne 0$ Trả lời
1.
Để $\tan4x$ xác định:
ĐK: $\cos 4x\ne 0$
$\Leftrightarrow 4x\ne \dfrac{\pi}{2}+k\pi$
$\Leftrightarrow x\ne\dfrac{\pi}{8}+\dfrac{k\pi}{4}$
2.
Để $\tan x$, $\cot x$ xác định:
ĐK: $\cos x\ne 0; \sin x\ne 0$
$\Leftrightarrow \sin2x\ne 0$
$\Leftrightarrow 2x\ne k\pi$
$\Leftrightarrow x\ne \dfrac{k\pi}{2}$
3.
ĐK: $\cos x\ne 0; x\ne 0$
$\Leftrightarrow x\ne \dfrac{\pi}{2}+k\pi; x\ne 0$