(12x-1)(6x-1)(4x-1)(3x-1)-330 phân tích đa tử thành nhâ tử 08/08/2021 Bởi Eden (12x-1)(6x-1)(4x-1)(3x-1)-330 phân tích đa tử thành nhâ tử
Đáp án:$= \left [ 6\left ( 12x^{2}-5x \right )+47 \right ]\left ( 12x+7 \right )\left ( x-1 \right )$Giải thích các bước giải: $\left ( 12x-1 \right )\left ( 6x-1 \right )\left ( 4x-1 \right )\left ( 3x-1 \right )-330$$= \left [ \left ( 12x-1 \right )\left ( 3x-1 \right ) \right ]\left [ \left ( 6x-1 \right )\left ( 4x-1 \right ) \right ]-330$$= \left ( 36x^{2}-15x+1 \right )\left ( 24x^{2}-10x+1 \right )-330$$= \left [ 3\left ( 12x^{2}-5x \right )+ 1\right ]\left [ 2\left ( 12x^{2}-5x \right )+1 \right ]-330$$= 6\left ( 12x^{2}-5x \right )+5\left ( 12x^{2}-5x \right )-329$$= \left [ 6\left ( 12x^{2}-5x \right )+47 \right ]\left ( 12x^{2}-5x-7 \right )$$= \left [ 6\left ( 12x^{2}-5x+47 \right ) \right ]\left ( 12x+7 \right )\left ( x-1 \right )$ Bình luận
Đáp án:
$= \left [ 6\left ( 12x^{2}-5x \right )+47 \right ]\left ( 12x+7 \right )\left ( x-1 \right )$
Giải thích các bước giải:
$\left ( 12x-1 \right )\left ( 6x-1 \right )\left ( 4x-1 \right )\left ( 3x-1 \right )-330$
$= \left [ \left ( 12x-1 \right )\left ( 3x-1 \right ) \right ]\left [ \left ( 6x-1 \right )\left ( 4x-1 \right ) \right ]-330$
$= \left ( 36x^{2}-15x+1 \right )\left ( 24x^{2}-10x+1 \right )-330$
$= \left [ 3\left ( 12x^{2}-5x \right )+ 1\right ]\left [ 2\left ( 12x^{2}-5x \right )+1 \right ]-330$
$= 6\left ( 12x^{2}-5x \right )+5\left ( 12x^{2}-5x \right )-329$
$= \left [ 6\left ( 12x^{2}-5x \right )+47 \right ]\left ( 12x^{2}-5x-7 \right )$
$= \left [ 6\left ( 12x^{2}-5x+47 \right ) \right ]\left ( 12x+7 \right )\left ( x-1 \right )$