18/27+4/19+1/3= a, x-2/65= 4/39 b, 1/150-x=-4/25

18/27+4/19+1/3=
a, x-2/65= 4/39
b, 1/150-x=-4/25

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  1. $\frac{18}{27}+\frac{4}{19}+\frac{1}{3}$
    $=\frac{2}{3}+\frac{1}{3}+\frac{4}{19}$
    $=1+\frac{4}{19}$
    $=\frac{23}{19}$
    $a)$
    $x-\frac{2}{65}=\frac{4}{39}$
    $x=\frac{4}{39}+\frac{2}{65}$
    $x=\frac{260}{2535}+\frac{78}{2535}$
    $x=\frac{338}{2535}$
    $b)$

    $⇒x=\frac{4}{39}+\frac{2}{65}$
    $⇒x=\frac{338}{2535}$

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  2. $\frac{18}{27}$ + $\frac{4}{19}$ + $\frac{1}{3}$ 

    = $\frac{342}{513}$ + $\frac{108}{513}$ + $\frac{171}{513}$

    = $\frac{23}{19}$

    a, x – $\frac{2}{65}$ = $\frac{4}{39}$

                  x = $\frac{4}{39}$ + $\frac{2}{65}$

                  x = $\frac{2}{15}$.

           Vậy x = $\frac{2}{15}$.

    b,$\frac{1}{115}$ – x = $\frac{-4}{25}$ 

                  x = $\frac{1}{115}$ – $\frac{-4}{25}$

                  x = $\frac{97}{575}$.

            Vậy x = $\frac{97}{575}$.

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