(2+1)×(2^2+1)×(2^4+1)×....×(2^32+1)-2^64

Question

minhtu · Answer

Đáp án: A=(3^128-1)/2

Giải thích các bước giải: A=(3 + 1)(3^2 + 1)(3^4 + 1)(3^8 + 1)(3^16 + 1)(3^32 + 1)(3^64+1)

2A=2(3 + 1)(3^2 + 1)(3^4 + 1)(3^8 + 1)(3^16 + 1)(3^32 + 1)(3^64+1)

2A=(3-1)(3 + 1)(3^2 + 1)(3^4 + 1)(3^8 + 1)(3^16 + 1)(3^32 + 1)(3^64+1)

2A=(3^2-1)(3^2 + 1)(3^4 + 1)(3^8 + 1)(3^16 + 1)(3^32 + 1)(3^64+1)

2A=(3^4-1)(3^4 + 1)(3^8 + 1)(3^16 + 1)(3^32 + 1)(3^64+1)

2A=(3^8-1)(3^8 + 1)(3^16 + 1)(3^32 + 1)(3^64+1)

2A=(3^16-1)(3^16 + 1)(3^32 + 1)(3^64+1)

2A=(3^32 – 1)(3^32 + 1)(3^64+1)

2A=(3^64-1)(3^64+1)

2A=3^128-1

=>A=(3^128-1)/2

uyenthu · Answer

Đ&aacute;p &aacute;n:   $A= frac{3^{128}-1}{2}$    Giải th&iacute;ch c&aacute;c bước giải:

(2+1)×(2^2+1)×(2^4+1)×….×(2^32+1)-2^64