Toán 2) ( 1/2x + 3 ) ( 2x^3 – 6x^2 + 4x + 10 ) 10/07/2021 By Ivy 2) ( 1/2x + 3 ) ( 2x^3 – 6x^2 + 4x + 10 )
( 1/2x + 3 ) ( 2x^3 – 6x^2 + 4x + 10 ) =($\frac{x}{2}$ + 3)(2x³-6x²+4x+10) =$\frac{3x+18}{6}$ . (2x³-6x²+4x+10) =$\frac{6x^4-18x^3+12^2+30x+36x^3-108x^2+72x+180}{6}$ =$\frac{6x^4+18x^3-96x^2+102x+180}{6}$ =$\frac{6.(x^4+3x^3-16x^2+17x+30}{6}$ =$x^{4}$+3x³-16x²+17x+30 Trả lời
`(1/2x+3)(2x^3-6x^2+4x+10)` `=1/2x.2x^3-1/2x.6x^2+1/2x.4x+1/2x.10+3.2x^3-3.6x^2+3.4x+3.10` `=x^4-3x^3+2x^2+5x+6x^3-18x^2+12x+30` `=x^4+(6x^3-3x^3)+(2x^2-18x^2)+(5x+12x)+30` `=x^4+3x^3-16x^2+17x+30` Trả lời
( 1/2x + 3 ) ( 2x^3 – 6x^2 + 4x + 10 )
=($\frac{x}{2}$ + 3)(2x³-6x²+4x+10)
=$\frac{3x+18}{6}$ . (2x³-6x²+4x+10)
=$\frac{6x^4-18x^3+12^2+30x+36x^3-108x^2+72x+180}{6}$
=$\frac{6x^4+18x^3-96x^2+102x+180}{6}$
=$\frac{6.(x^4+3x^3-16x^2+17x+30}{6}$
=$x^{4}$+3x³-16x²+17x+30
`(1/2x+3)(2x^3-6x^2+4x+10)`
`=1/2x.2x^3-1/2x.6x^2+1/2x.4x+1/2x.10+3.2x^3-3.6x^2+3.4x+3.10`
`=x^4-3x^3+2x^2+5x+6x^3-18x^2+12x+30`
`=x^4+(6x^3-3x^3)+(2x^2-18x^2)+(5x+12x)+30`
`=x^4+3x^3-16x^2+17x+30`