2 ^ (x + 1) = 4 ^ 7 / (4 ^ 5) giúp em v ah 01/12/2021 Bởi Bella 2 ^ (x + 1) = 4 ^ 7 / (4 ^ 5) giúp em v ah
2 ^ (x + 1) = 4 ^ 7 / (4 ^ 5) =>2 ^ (x + 1) = 4^7-5 =>2^(x+1)=4^2 =>2^(x+1)=16 =>2^(x+1)=2^4 =>x+1=4 =>x=4-1 =>x=3 Bình luận
`2^(x+1)` = `(4^7)/(4^5)` `2^(x+1)` = `4^2` `2^(x+1)` = 16 `2^(x+1)` = `2^4` `=>` x + 1 = 4 `=>` x = 4 – 1 `=>` x = 3 Vậy x = 3. Bình luận
2 ^ (x + 1) = 4 ^ 7 / (4 ^ 5)
=>2 ^ (x + 1) = 4^7-5
=>2^(x+1)=4^2
=>2^(x+1)=16
=>2^(x+1)=2^4
=>x+1=4
=>x=4-1
=>x=3
`2^(x+1)` = `(4^7)/(4^5)`
`2^(x+1)` = `4^2`
`2^(x+1)` = 16
`2^(x+1)` = `2^4`
`=>` x + 1 = 4
`=>` x = 4 – 1
`=>` x = 3
Vậy x = 3.