x^2+10 x+25 x^2+14x+49 4x^2+4x+1 9x^2+30x+25 x^2+6xy+9y^2 16x^2+24xy+9y^2 (2x+1)^2+12(2x+1)+36 (x^2+2x)^2+2(x^2+2x)+1 vân dụng hằng đẳng thức (A+B)^ph

0 bình luận về “x^2+10 x+25 x^2+14x+49 4x^2+4x+1 9x^2+30x+25 x^2+6xy+9y^2 16x^2+24xy+9y^2 (2x+1)^2+12(2x+1)+36 (x^2+2x)^2+2(x^2+2x)+1 vân dụng hằng đẳng thức (A+B)^ph”

1. `1)x²+10x+25`

   `=x²+2.x.5+5²`

   `=(x+5)²`

   `2)x²+14x+49`

   `=x²+2.x.7+7²`

   `=(x+7)²`

   `3)4x²+4x+1`

   `=(2x)²+2.2x.1+1²`

   `=(2x+1)²`

   `4)9x²+30x+25`

   `=(3x)²+2.3x.5+5²`

   `=(3x+5)²`

   `5)x²+6xy+9y²`

   `=x²+2.x.3y+(3y)²`

   `=(x+3y)²`

   `6)16x²+24xy+9y²`

   `=(4x)²+2.4x.3y+(3y)²`

   `=(4x+3y)²`

   `7)(2x+1)²+12(2x+1)+36`

   `=(2x+1)²+2.(2x+1).6+6²`

   `=(2x+1+6)²`

   `=(2x+7)²`

   `8)(x²+2x)²+2(x²+2x)+1`

   `=(x²+2x)²+2.(x²+2x).1+1²`

   `=(x²+2x+1)²`

   `=[(x+1)²]²`

   `=(x+1)^4`

    

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2. Đáp án:

    

   Giải thích các bước giải:

   `x^2+10 x+25=(x)^2+2.5x+(5)^2=(x+5)^2`

   `x^2+14x+49=(x)^2+2.7x+(7)^2=(x+7)^2`

   `4x^2+4x+1=(2x)^2+2.2.1.x+(1)^2=(2x+1)^2`

   `9x^2+30x+25=(3x)^2+2.3.5x+(5)^2=(3x+5)^2`

   `x^2+6xy+9y^2=(x)^2+2.3xy+(3y)^2=(x+3y)^2`

   `16x^2+24xy+9y^2=(4x)^2+2.4.3x+(3y)^2=(4x+3y)^2`

   `(2x+1)^2+12(2x+1)+36`

   Đặt `2x+1=t`

   `t^2+12t+36=(t)^2+2.6t+(6)^2=(t+6)^2=[(2x+1+6)]^2=(2x+7)^2`

   `(x^2+2x)^2+2(x^2+2x)+1`

   Đặt `x^2+2x=a`

   `a^2+2a+1=(a)^2+1.2a+(1)^2=(a+1)^2=[(x^2+2x+1)]^2=[(x+1)^2]^2=(x+1)^4`

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