2^12 . 3^5 – 4^6 . 81 / ( 2^2 . 3 )^6 + 8^4 . 3^5

Đáp án:

 `=1/6`

Giải thích các bước giải:

`(2^12 . 3^5 – 4^6 . 81) /( ( 2^2 . 3 )^6 + 8^4 . 3^5)`
`=(2^12 . 3^5 – (2^2)^6 . 3^4) /( ( 2^2)^6  . 3 ^6 + (2^3)^4 . 3^5)`
`=(2^12 . 3^5 – 2^12 . 3^4) /( 2^12  . 3 ^6 + 2^12 . 3^5)`
`=(2^12 .( 3^5 – 3^4)) /( 2^12  .( 3 ^6 +  3^5))`
`=(3^5 – 3^4 )/(3^6 + 3^5)`
`=(3^4 . ( 3-1))/(3^5 . ( 3+1))`
`=(3^4 . 2)/(3^5 . 4)`
`=(1.1)/(3.2)`
`=1/6`