( $2^{2016}$ + $2^{2017}$ + $2^{2018}$ +. . .+ $2^{2030}$ ) . ( $3^{4}$.27- $6^{3}$. $3^{4}$: $2^{3}$)
mình cần gấp, các bạn giải chi tiết hộ mình nhé ^^
( $2^{2016}$ + $2^{2017}$ + $2^{2018}$ +. . .+ $2^{2030}$ ) . ( $3^{4}$.27- $6^{3}$. $3^{4}$: $2^{3}$) mình cần gấp, các bạn giải chi tiết hộ mình n
By Emery
Đáp án: 0
Giải thích các bước giải:
( $2^{2016}$ + $2^{2017}$ + $2^{2018}$ + … + $2^{2030}$ ) . ( $3^{4}$ . 27 – $6^{3}$ . $3^{4}$ : $2^{3}$ )
= ( $2^{2016}$ + $2^{2017}$ + $2^{2018}$ + … + $2^{2030}$ ) . ( $3^{4}$ . $3^{3}$ – $6^{3}$ : $2^{3}$ . $3^{4}$ )
= ( $2^{2016}$ + $2^{2017}$ + $2^{2018}$ + … + $2^{2030}$ ) . ( $3^{4}$ . $3^{3}$ – $3^{3}$ . $3^{4}$ )
= ( $2^{2016}$ + $2^{2017}$ + $2^{2018}$ + … + $2^{2030}$ ) . 0
= 0
Đáp án:
Giải thích các bước giải:
Ta có:
$(2^{2016} + 2^{2017} + 2^{2018} +… 2^{2030}) . (3^4.27 – 6^3.3^4:2^3)$
$= (2^{2016} + 2^{2017} + 2^{2018} +… 2^{2030}) . [3^4.(27 – 6^3:2^3)]$
$=(2^{2016} + 2^{2017} + 2^{2018} +… 2^{2030}) . [3^4.(27- 3^3)]$
$= (2^{2016} + 2^{2017} + 2^{2018} +… 2^{2030}) . [3^4.(27 – 27)]$
$= (2^{2016} + 2^{2017} + 2^{2018} +… 2^{2030}) . (3^4 . 0)$
$= (2^{2016} + 2^{2017} + 2^{2018} +… 2^{2030}) . 0$
$= 0$