( 2x – 3 ) ( x + 2 ) = 3 – ( x – 6 ) ( 3x – 2) 07/07/2021 Bởi Harper ( 2x – 3 ) ( x + 2 ) = 3 – ( x – 6 ) ( 3x – 2)
`( 2x – 3 ) ( x + 2 ) = 3 – ( x – 6 ) ( 3x – 2)` `⇔( 2x – 3 ) ( x + 2 )-( x – 6 ) ( 2x – 3)=3` `⇔( 2x – 3 ) ( x + 2 -x + 6 ) =3` `⇔( 2x – 3 ) ( x + 2 -x + 6 )=3` `⇔( 2x – 3 )8=3` `⇔ 2x – 3 =3/8` `⇔2x=(27)/8` `⇔x=(27)/(16)` Bình luận
Đáp án: Giải thích các bước giải: `(2x-3)(x+2)=3-(x-6)(3x-2)` `<=>2x^2+4x-3x-6=3-(3x^2-2x-18x+12)` `<=>2x^2+x-6=3-(3x^2-20x+12)` `<=>2x^2+x-6=3-3x^2+20x-12` `<=>5x^2-19x+3=0` `<=>5(x^2-19/5 x+361/100)-301/20=0` `<=>5(x-19/10)^2=301/20` `<=>(x-19/10)^2=301/100` `<=>x=+-\sqrt{301}/10 +19/10` Vậy `S={+-\sqrt{301}/10 +19/10}` Bình luận
`( 2x – 3 ) ( x + 2 ) = 3 – ( x – 6 ) ( 3x – 2)`
`⇔( 2x – 3 ) ( x + 2 )-( x – 6 ) ( 2x – 3)=3`
`⇔( 2x – 3 ) ( x + 2 -x + 6 ) =3`
`⇔( 2x – 3 ) ( x + 2 -x + 6 )=3`
`⇔( 2x – 3 )8=3`
`⇔ 2x – 3 =3/8`
`⇔2x=(27)/8`
`⇔x=(27)/(16)`
Đáp án:
Giải thích các bước giải:
`(2x-3)(x+2)=3-(x-6)(3x-2)`
`<=>2x^2+4x-3x-6=3-(3x^2-2x-18x+12)`
`<=>2x^2+x-6=3-(3x^2-20x+12)`
`<=>2x^2+x-6=3-3x^2+20x-12`
`<=>5x^2-19x+3=0`
`<=>5(x^2-19/5 x+361/100)-301/20=0`
`<=>5(x-19/10)^2=301/20`
`<=>(x-19/10)^2=301/100`
`<=>x=+-\sqrt{301}/10 +19/10`
Vậy `S={+-\sqrt{301}/10 +19/10}`