2`x^4` – 13`x^3` + 24`x^2`- 13x + 2 = 0 Giải PT 26/08/2021 Bởi Lyla 2`x^4` – 13`x^3` + 24`x^2`- 13x + 2 = 0 Giải PT
Đáp án: \(\left[ \begin{array}{l}x = \dfrac{1}{2}\\x = 11,21328686\end{array} \right.\) Giải thích các bước giải: \(\begin{array}{l}2{x^4} – 13{x^3} + 24{x^2} – 13x + 2 = 0\\ \to 2{x^4} – {x^3} – 12{x^3} + 6{x^2} + 18{x^2} – 9x – 4x + 2 = 0\\ \to {x^3}\left( {2x – 1} \right) – 12{x^2}\left( {2x – 1} \right) + 9x\left( {2x – 1} \right) – 2\left( {2x – 1} \right) = 0\\ \to \left( {2x – 1} \right)\left( {{x^3} – 12{x^2} + 9x – 2} \right) = 0\\ \to \left[ \begin{array}{l}x = \dfrac{1}{2}\\{x^3} – 12{x^2} + 9x – 2 = 0\end{array} \right.\\ \to \left[ \begin{array}{l}x = \dfrac{1}{2}\\x = 11,21328686\end{array} \right.\end{array}\) Bình luận
Đáp án:
\(\left[ \begin{array}{l}
x = \dfrac{1}{2}\\
x = 11,21328686
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
2{x^4} – 13{x^3} + 24{x^2} – 13x + 2 = 0\\
\to 2{x^4} – {x^3} – 12{x^3} + 6{x^2} + 18{x^2} – 9x – 4x + 2 = 0\\
\to {x^3}\left( {2x – 1} \right) – 12{x^2}\left( {2x – 1} \right) + 9x\left( {2x – 1} \right) – 2\left( {2x – 1} \right) = 0\\
\to \left( {2x – 1} \right)\left( {{x^3} – 12{x^2} + 9x – 2} \right) = 0\\
\to \left[ \begin{array}{l}
x = \dfrac{1}{2}\\
{x^3} – 12{x^2} + 9x – 2 = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \dfrac{1}{2}\\
x = 11,21328686
\end{array} \right.
\end{array}\)