$(2,4x-36):1\frac{5}{7}=-1$ $\frac{1}{3}.x-0,5.x=0,75$ $\frac{1}{2}.x+$ $\frac{3}{5}.(x-2)=3$

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1. $(2,4x-36):1\dfrac{5}{7}=-1$

   $\to(2,4x-36):\dfrac{12}{7}=-1$

   $\to 2,4x-36=-1.\dfrac{12}{7}$

   $\to 2,4x-36=\dfrac{-12}{7}$

   $\to 2,4x=\dfrac{-12}{7}+36$

   $\to 2,4x=\dfrac{240}{7}$

   $\to x=\dfrac{240}{7}:2,4$

   $\to x=\dfrac{240}{7}:\dfrac{12}{5}$

   $\to x=\dfrac{100}{7}$

   Vậy $x=\dfrac{100}{7}$

   $\dfrac{1}{3}x-0,5x=0,75$

   $\to (\dfrac{1}{3}-0,5)x=0,75$

   $\to \dfrac{-1}{6}x=\dfrac{3}{4}$

   $\to x=\dfrac{3}{4}:\dfrac{-1}{6}$

   $\to x=\dfrac{-9}{2}$

   Vậy $x=\dfrac{-9}{2}$

   $\dfrac{1}{2}x+\dfrac{3}{5}(x-2)=3$

   $\to \dfrac{1}{2}x+\dfrac{3}{5}.x-\dfrac{3}{5}.2=3$

   $\to \dfrac{1}{2}x+\dfrac{3}{5}.x-\dfrac{6}{5}=3$

   $\to (\dfrac{1}{2}+\dfrac{3}{5})x=\dfrac{6}{5}+3$

   $\to \dfrac{11}{10}x=\dfrac{21}{5}$

   $\to x=\dfrac{21}{5}:\dfrac{11}{10}$

   $\to x=\dfrac{42}{11}$

   Vậy $x=\dfrac{42}{11}$

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