2/căn 3 -1 trừ 1/căn 3-2 cộng 12/căn 3 +3 giúp mình vs 11/08/2021 Bởi Hailey 2/căn 3 -1 trừ 1/căn 3-2 cộng 12/căn 3 +3 giúp mình vs
CHÚC BẠN HỌC TỐT !!!!!!!! Đáp án: $9$ Giải thích các bước giải: `{2}/{\sqrt{3} – 1} – {1}/{\sqrt{3} – 2} + {12}/{\sqrt{3} + 3}` $=$ `{2(\sqrt{3} + 1)}/{(\sqrt{3} – 1)(\sqrt{3} + 1)} – {\sqrt{3} + 2}/{(\sqrt{3} – 2)(\sqrt{3} + 2)} + {12(3 – \sqrt{3})}/{(\sqrt{3} + 3)(3 – \sqrt{3})}` $=$ `{2(\sqrt{3} + 1)}/{3 – 1} – {2 + \sqrt{3}}/{3 – 4} + {12(3 – \sqrt{3})}/{9 – 3}` $=$ `{2(\sqrt{3} + 1)}/{2} – {2 + \sqrt{3}}/{- 1} + {12(3 – \sqrt{3})}/{6}` $= (\sqrt{3} + 1) + (2 + \sqrt{3}) + 2(3 – \sqrt{3})$ $= \sqrt{3} + 1 + 2 + \sqrt{3} + 6 – 2\sqrt{3}$ $= 9$ Bình luận
$\dfrac{2}{\sqrt[]{3}-1} – \dfrac{1}{\sqrt[]{3}-2} + \dfrac{12}{\sqrt[]{3}+3}$ $ = \dfrac{2.(\sqrt[]{3}+1)}{3-1} – \dfrac{1.(\sqrt[]{3}+2)}{3-4} + \dfrac{12.(\sqrt[]{3}-3)}{3-9}$ $ = \sqrt[]{3} + 1 + \sqrt[]{3} + 2 – 2.(\sqrt[]{3}-3)$ $ = 2\sqrt[]{3} + 3 – 2\sqrt[]{3} + 6 = 9 $ Bình luận
CHÚC BẠN HỌC TỐT !!!!!!!!
Đáp án:
$9$
Giải thích các bước giải:
`{2}/{\sqrt{3} – 1} – {1}/{\sqrt{3} – 2} + {12}/{\sqrt{3} + 3}`
$=$ `{2(\sqrt{3} + 1)}/{(\sqrt{3} – 1)(\sqrt{3} + 1)} – {\sqrt{3} + 2}/{(\sqrt{3} – 2)(\sqrt{3} + 2)} + {12(3 – \sqrt{3})}/{(\sqrt{3} + 3)(3 – \sqrt{3})}`
$=$ `{2(\sqrt{3} + 1)}/{3 – 1} – {2 + \sqrt{3}}/{3 – 4} + {12(3 – \sqrt{3})}/{9 – 3}`
$=$ `{2(\sqrt{3} + 1)}/{2} – {2 + \sqrt{3}}/{- 1} + {12(3 – \sqrt{3})}/{6}`
$= (\sqrt{3} + 1) + (2 + \sqrt{3}) + 2(3 – \sqrt{3})$
$= \sqrt{3} + 1 + 2 + \sqrt{3} + 6 – 2\sqrt{3}$
$= 9$
$\dfrac{2}{\sqrt[]{3}-1} – \dfrac{1}{\sqrt[]{3}-2} + \dfrac{12}{\sqrt[]{3}+3}$
$ = \dfrac{2.(\sqrt[]{3}+1)}{3-1} – \dfrac{1.(\sqrt[]{3}+2)}{3-4} + \dfrac{12.(\sqrt[]{3}-3)}{3-9}$
$ = \sqrt[]{3} + 1 + \sqrt[]{3} + 2 – 2.(\sqrt[]{3}-3)$
$ = 2\sqrt[]{3} + 3 – 2\sqrt[]{3} + 6 = 9 $