2-|$\frac{3}{2}$- $\frac{1}{4}$|=|$\frac{5}{4}$| 23/08/2021 Bởi Kaylee 2-|$\frac{3}{2}$- $\frac{1}{4}$|=|$\frac{5}{4}$|
$2-|\frac{3}{2x}-\frac{1}{4}|=|-\frac{5}{4}|$ $⇔|\frac{3}{2}x-\frac{1}{4}|=2-\frac{5}{4}$ $⇔|\frac{3}{2}x-\frac{1}{4}|=\frac{3}{4}$ \(⇔\left[ \begin{array}{l}\frac{3}{2}x-\frac{1}{4}=\frac{3}{4}\\\frac{3}{2}x-\frac{1}{4}=\frac{-3}{4}\end{array} \right.\)\(⇔\left[ \begin{array}{l}\frac{3}{2}x=\frac{1}{4}+\frac{3}{4}=1\\\frac{3}{2}x=\frac{-3}{4}+\frac{1}{4}=\frac{-1}{2}\end{array} \right.\)\(⇔\left[ \begin{array}{l}x=\frac{2}{3}\\x=\frac{-1}{3}\end{array} \right.\) Vậy… Bình luận
$2-|\frac{3}{2x}-\frac{1}{4}|=|-\frac{5}{4}|$
$⇔|\frac{3}{2}x-\frac{1}{4}|=2-\frac{5}{4}$
$⇔|\frac{3}{2}x-\frac{1}{4}|=\frac{3}{4}$
\(⇔\left[ \begin{array}{l}\frac{3}{2}x-\frac{1}{4}=\frac{3}{4}\\\frac{3}{2}x-\frac{1}{4}=\frac{-3}{4}\end{array} \right.\)
\(⇔\left[ \begin{array}{l}\frac{3}{2}x=\frac{1}{4}+\frac{3}{4}=1\\\frac{3}{2}x=\frac{-3}{4}+\frac{1}{4}=\frac{-1}{2}\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=\frac{2}{3}\\x=\frac{-1}{3}\end{array} \right.\)
Vậy…
Đáp án:
Giải thích các bước giải:
Chúc bn hok tốt !