Toán 2, tính ( x – 5 ) ^13 = 36 .( x – 5 ) ^15 16/11/2021 By Eva 2, tính ( x – 5 ) ^13 = 36 .( x – 5 ) ^15
Đáp án: `x=5 \ or \ x=31/6\ or \ x=29/6` Giải thích các bước giải: `(x-5)^13=36.(x-5)^15` `->36.(x-5)^15-(x-5)^13=0` `->(x-5)^13[36(x-5)^2-1]=0` `TH1:` `(x-5)^13=0` `->x-5=0` `->x=5` `TH2:` `36(x-5)^2-1=0` `->36(x-5)^2=1` `->(x-5)^2=1/36` `->x-5=1/6\ or \ x-5=-1/6` `->x=31/6\ or \ x=29/6` Vậy `x=5 \ or\ x=31/6\ or \ x=29/6` Trả lời
Giải thích các bước giải: `( x – 5 ) ^13 = 36 .( x – 5 ) ^15``=>(x-5)^13-36.(x-5)^15=0``=>(x-5)^13 . 1 -36 .(x-5)^2 .(x-5)^13 =0``=>(x-5)^13 .[1-36 . (x-5)^2]=0``=>`\(\left[ \begin{array}{l}(x-5)^{13}=0\\1-36.(x-5)^2 =0\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x-5=0\\36.(x-5)^2=1\end{array} \right.\)`=>`\(\left[ \begin{array}{l}x=0+5\\(x-5)^2=1:36\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=5\\x-5=\dfrac{1}{6} \text{hoặc} x-5=\dfrac{-1}{6}\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=5\\x=\dfrac{31}{6} \text{hoặc} x=\dfrac{29}{6}\end{array} \right.\) Trả lời
Đáp án:
`x=5 \ or \ x=31/6\ or \ x=29/6`
Giải thích các bước giải:
`(x-5)^13=36.(x-5)^15`
`->36.(x-5)^15-(x-5)^13=0`
`->(x-5)^13[36(x-5)^2-1]=0`
`TH1:`
`(x-5)^13=0`
`->x-5=0`
`->x=5`
`TH2:`
`36(x-5)^2-1=0`
`->36(x-5)^2=1`
`->(x-5)^2=1/36`
`->x-5=1/6\ or \ x-5=-1/6`
`->x=31/6\ or \ x=29/6`
Vậy `x=5 \ or\ x=31/6\ or \ x=29/6`
Giải thích các bước giải:
`( x – 5 ) ^13 = 36 .( x – 5 ) ^15`
`=>(x-5)^13-36.(x-5)^15=0`
`=>(x-5)^13 . 1 -36 .(x-5)^2 .(x-5)^13 =0`
`=>(x-5)^13 .[1-36 . (x-5)^2]=0`
`=>`\(\left[ \begin{array}{l}(x-5)^{13}=0\\1-36.(x-5)^2 =0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x-5=0\\36.(x-5)^2=1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=0+5\\(x-5)^2=1:36\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=5\\x-5=\dfrac{1}{6} \text{hoặc} x-5=\dfrac{-1}{6}\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=5\\x=\dfrac{31}{6} \text{hoặc} x=\dfrac{29}{6}\end{array} \right.\)