Toán 2018|x-1|+(x-1) ²)=2019|1-x| PLZ HELP ME đa tạ 02/12/2021 By Rylee 2018|x-1|+(x-1) ²)=2019|1-x| PLZ HELP ME đa tạ
`2018.|x-1|+(x-1)^2=2019.|1-x|` `⇒2018.|x-1|+(x-1)^2=2019.|x-1|` `⇒(x-1)^2=2019.|x-1|-2018.|x-1|` `⇒(x-1)^2=|x-1|.(2019-2018)` `⇒(x-1)^2=|x-1|` Để `(x-1)^2` vẫn bằng `|x-1|` thì `(x-1)` bình phương thì vẫn dữ bằng `|x-1|` \(\left[ \begin{array}{l}x-1=1\\x-1=0\\x-1=-1\end{array} \right.\) ⇒\(\left[ \begin{array}{l}x=2\\x=1\\x=0\end{array} \right.\) Trả lời
Giải thích các bước giải:
`2018.|x-1|+(x-1)^2=2019.|1-x|`
`⇒2018.|x-1|+(x-1)^2=2019.|x-1|`
`⇒(x-1)^2=2019.|x-1|-2018.|x-1|`
`⇒(x-1)^2=|x-1|.(2019-2018)`
`⇒(x-1)^2=|x-1|`
Để `(x-1)^2` vẫn bằng `|x-1|`
thì `(x-1)` bình phương thì vẫn dữ bằng `|x-1|`
\(\left[ \begin{array}{l}x-1=1\\x-1=0\\x-1=-1\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=2\\x=1\\x=0\end{array} \right.\)