-28-7.|-3x+15|=-70 |18-2|-x+5||=12 12-2.{-x+3}=-38 -20+3.{2x+1}=-101 giúp mình với 08/07/2021 Bởi Parker -28-7.|-3x+15|=-70 |18-2|-x+5||=12 12-2.{-x+3}=-38 -20+3.{2x+1}=-101 giúp mình với
Đáp án: d) x=-14 Giải thích các bước giải: \(\begin{array}{l}a) – 28 – 7\left| { – 3x + 15} \right| = – 70\\ \to 7\left| { – 3x + 15} \right| = 42\\ \to \left| { – 3x + 15} \right| = 6\\ \to \left[ \begin{array}{l} – 3x + 15 = 6\\ – 3x + 15 = – 6\end{array} \right.\\ \to \left[ \begin{array}{l}x = 3\\x = – 7\end{array} \right.\\b)\left| {18 – 2\left| { – x + 5} \right|} \right| = 12\\ \to \left[ \begin{array}{l}18 – 2\left| { – x + 5} \right| = 12\\18 – 2\left| { – x + 5} \right| = – 12\end{array} \right.\\ \to \left[ \begin{array}{l}2\left| { – x + 5} \right| = 6\\2\left| { – x + 5} \right| = 30\end{array} \right.\\ \to \left[ \begin{array}{l}\left| { – x + 5} \right| = 3\\\left| { – x + 5} \right| = 15\end{array} \right.\\ \to \left[ \begin{array}{l} – x + 5 = 3\\ – x + 5 = – 3\\ – x + 5 = 15\\ – x + 5 = – 15\end{array} \right. \to \left[ \begin{array}{l}x = 2\\x = 8\\x = – 10\\x = 20\end{array} \right.\\c)12 – 2\left( { – x + 3} \right) = – 38\\ \to 2\left( { – x + 3} \right) = 50\\ \to 3 – x = 25\\ \to x = – 22\\d) – 20 + 3\left( {2x + 1} \right) = – 101\\ \to 3\left( {2x + 1} \right) = – 81\\ \to 2x + 1 = – 27\\ \to x = – 14\end{array}\) Bình luận
Đáp án:
d) x=-14
Giải thích các bước giải:
\(\begin{array}{l}
a) – 28 – 7\left| { – 3x + 15} \right| = – 70\\
\to 7\left| { – 3x + 15} \right| = 42\\
\to \left| { – 3x + 15} \right| = 6\\
\to \left[ \begin{array}{l}
– 3x + 15 = 6\\
– 3x + 15 = – 6
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 3\\
x = – 7
\end{array} \right.\\
b)\left| {18 – 2\left| { – x + 5} \right|} \right| = 12\\
\to \left[ \begin{array}{l}
18 – 2\left| { – x + 5} \right| = 12\\
18 – 2\left| { – x + 5} \right| = – 12
\end{array} \right.\\
\to \left[ \begin{array}{l}
2\left| { – x + 5} \right| = 6\\
2\left| { – x + 5} \right| = 30
\end{array} \right.\\
\to \left[ \begin{array}{l}
\left| { – x + 5} \right| = 3\\
\left| { – x + 5} \right| = 15
\end{array} \right.\\
\to \left[ \begin{array}{l}
– x + 5 = 3\\
– x + 5 = – 3\\
– x + 5 = 15\\
– x + 5 = – 15
\end{array} \right. \to \left[ \begin{array}{l}
x = 2\\
x = 8\\
x = – 10\\
x = 20
\end{array} \right.\\
c)12 – 2\left( { – x + 3} \right) = – 38\\
\to 2\left( { – x + 3} \right) = 50\\
\to 3 – x = 25\\
\to x = – 22\\
d) – 20 + 3\left( {2x + 1} \right) = – 101\\
\to 3\left( {2x + 1} \right) = – 81\\
\to 2x + 1 = – 27\\
\to x = – 14
\end{array}\)