3(1-x)-2x(x-1)=0 Giúp mình nha, thank youuuuuu

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1. $3.(1-x) – 2x.(x-1) =0$

   $⇔ -3.(x-1) – 2x.(x-1) = 0$

   $⇔ (x-1).(-3 -2x) = 0$

   $⇒$ \(\left[ \begin{array}{l}x-1=0\\-3-2x=0\end{array} \right.\) 

   $⇔$ \(\left[ \begin{array}{l}x=1\\x=\dfrac{-3}{2}\end{array} \right.\) 

       Vậy $x$ $∈$ {$\dfrac{-3}{2};1$}

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2. `3(1-x)-2x(x-1)=0`

   `⇒3(1-x)+2x(1-x)=0`

   `⇒(2x+3)(1-x)=0`

   \(⇒\left[ \begin{array}{l}2x+3=0⇒2x=-3⇒x=\dfrac{-3}{2}\\1-x=0⇒x=1\end{array} \right.\)

   Vậy `S={1;{-3}/{2}}`

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