3. x(2x^2 – 3) – x^2(5x + 1) + x^2. 4. 3x(x – 2) – 5x(1 – x) – 8(x^2 – 3) 12/10/2021 Bởi Kennedy 3. x(2x^2 – 3) – x^2(5x + 1) + x^2. 4. 3x(x – 2) – 5x(1 – x) – 8(x^2 – 3)
`3.x(2x^2 – 3) – x^2(5x + 1) + x^2. 4. 3x(x – 2) – 5x(1 – x) – 8(x^2 – 3)` `=6x^3 -9x-5x^3-x^2 +12x^4-24x^3-5x+5x^2-8x^2+24` `=12x^4+(6x^3-5x^3-24x^3)+(-x^2+5x^2-8x^2)+(-9x-5x)+24` `=12x^4-23x^3-4x^2-14x+24` Bình luận
3. x(2x² – 3) – x²(5x + 1) + x². 4. 3x(x – 2) – 5x(1 – x) – 8(x² – 3) =(6x³-9x)-(5x³+x²)+(12$x^{4}$ -24x³)-(5x-5x²)-(8x²-24) =6x³-9x-5x³-x²+12$x^{4}$-24x³-5x+5x²-8x²+24 =-14x-4x²-23x³+12$x^{4}$+24 Bình luận
`3.x(2x^2 – 3) – x^2(5x + 1) + x^2. 4. 3x(x – 2) – 5x(1 – x) – 8(x^2 – 3)`
`=6x^3 -9x-5x^3-x^2 +12x^4-24x^3-5x+5x^2-8x^2+24`
`=12x^4+(6x^3-5x^3-24x^3)+(-x^2+5x^2-8x^2)+(-9x-5x)+24`
`=12x^4-23x^3-4x^2-14x+24`
3. x(2x² – 3) – x²(5x + 1) + x². 4. 3x(x – 2) – 5x(1 – x) – 8(x² – 3)
=(6x³-9x)-(5x³+x²)+(12$x^{4}$ -24x³)-(5x-5x²)-(8x²-24)
=6x³-9x-5x³-x²+12$x^{4}$-24x³-5x+5x²-8x²+24
=-14x-4x²-23x³+12$x^{4}$+24