( (3$x^{2}$ -2y)$^{3}$ ($x^{2}$ -$\frac{1}{3}$ ).($x^{4}$ +$\frac{1}{3}$ $x^{2}$ +$\frac{1}{9}$ )

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1. (3x^2-2y^3)

   =(3x^2)^3-3(3x^2)^2.2y+2.3x.(2y^2)^2-(2y)^3

   =27x^6-54.x^4.y+24x^2.y^2-8y^3

   (x^2-1/3).(x^4+1/3.x^2+1/9)

   =(x^2-1/3).((x^2)^2+1/3.x^2+(1/3)^2)

   =x^3-(1/3)^3

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