(-3)^(x-5)=-1/27 (-5)^(x+3)=-1/125 2*3^(x+2)+4*3^(x+1)=10*3^6 6*8^(x-1)+8^(x+1)=6*8^19+8^21 19/07/2021 Bởi Eva (-3)^(x-5)=-1/27 (-5)^(x+3)=-1/125 2*3^(x+2)+4*3^(x+1)=10*3^6 6*8^(x-1)+8^(x+1)=6*8^19+8^21
Đáp án: $\begin{array}{l}a){\left( { – 3} \right)^{x – 5}} = – \dfrac{1}{{27}}\\ \Rightarrow {\left( { – 3} \right)^{x – 5}} = \dfrac{1}{{{{\left( { – 3} \right)}^3}}}\\ \Rightarrow {\left( { – 3} \right)^{x – 5}} = {\left( { – 3} \right)^{ – 3}}\\ \Rightarrow x – 5 = – 3\\ \Rightarrow x = – 3 + 5 = 2\\Vay\,x = 2\\b){\left( { – 5} \right)^{x + 3}} = – \dfrac{1}{{125}}\\ \Rightarrow {\left( { – 5} \right)^{x + 3}} = {\left( { – 5} \right)^{ – 3}}\\ \Rightarrow x + 3 = – 3\\ \Rightarrow x = – 6\\Vay\,x = – 6\\c){2.3^{x + 2}} + {4.3^{x + 1}} = {10.3^6}\\ \Rightarrow {2.3^{x + 1}}.3 + {4.3^{x + 1}} = {10.3^6}\\ \Rightarrow {3^{x + 1}}.\left( {6 + 4} \right) = {10.3^6}\\ \Rightarrow {3^{x + 1}}.10 = {10.3^6}\\ \Rightarrow {3^{x + 1}} = {3^6}\\ \Rightarrow x + 1 = 6\\ \Rightarrow x = 5\\Vay\,x = 5\\d){6.8^{x – 1}} + {8^{x + 1}} = {6.8^{19}} + {8^{21}}\\ \Rightarrow {6.8^{x – 1}} + {8^{x – 1 + 2}} = {6.8^{19}} + {8^{19 + 2}}\\ \Rightarrow {8^{x – 1}}\left( {6 + {8^2}} \right) = {8^{19}}.\left( {6 + {8^2}} \right)\\ \Rightarrow {8^{x – 1}} = {8^{19}}\\ \Rightarrow x – 1 = 19\\ \Rightarrow x = 20\\Vay\,x = 20\end{array}$ Bình luận
Đáp án:
$\begin{array}{l}
a){\left( { – 3} \right)^{x – 5}} = – \dfrac{1}{{27}}\\
\Rightarrow {\left( { – 3} \right)^{x – 5}} = \dfrac{1}{{{{\left( { – 3} \right)}^3}}}\\
\Rightarrow {\left( { – 3} \right)^{x – 5}} = {\left( { – 3} \right)^{ – 3}}\\
\Rightarrow x – 5 = – 3\\
\Rightarrow x = – 3 + 5 = 2\\
Vay\,x = 2\\
b){\left( { – 5} \right)^{x + 3}} = – \dfrac{1}{{125}}\\
\Rightarrow {\left( { – 5} \right)^{x + 3}} = {\left( { – 5} \right)^{ – 3}}\\
\Rightarrow x + 3 = – 3\\
\Rightarrow x = – 6\\
Vay\,x = – 6\\
c){2.3^{x + 2}} + {4.3^{x + 1}} = {10.3^6}\\
\Rightarrow {2.3^{x + 1}}.3 + {4.3^{x + 1}} = {10.3^6}\\
\Rightarrow {3^{x + 1}}.\left( {6 + 4} \right) = {10.3^6}\\
\Rightarrow {3^{x + 1}}.10 = {10.3^6}\\
\Rightarrow {3^{x + 1}} = {3^6}\\
\Rightarrow x + 1 = 6\\
\Rightarrow x = 5\\
Vay\,x = 5\\
d){6.8^{x – 1}} + {8^{x + 1}} = {6.8^{19}} + {8^{21}}\\
\Rightarrow {6.8^{x – 1}} + {8^{x – 1 + 2}} = {6.8^{19}} + {8^{19 + 2}}\\
\Rightarrow {8^{x – 1}}\left( {6 + {8^2}} \right) = {8^{19}}.\left( {6 + {8^2}} \right)\\
\Rightarrow {8^{x – 1}} = {8^{19}}\\
\Rightarrow x – 1 = 19\\
\Rightarrow x = 20\\
Vay\,x = 20
\end{array}$