a) $\frac{3}{5}$ x – $\frac{1}{4}$ = $\frac{5}{2}$ ⇔ $\frac{3}{5}$ x = $\frac{5}{2}$ + $\frac{1}{4}$ ⇔ $\frac{3}{5}$ x = $\frac{10}{4}$ + $\frac{1}{4}$ ⇔ $\frac{3}{5}$ x = $\frac{11}{4}$ ⇔ x = $\frac{11}{4}$ : $\frac{3}{5}$ ⇔ x = $\frac{55}{12}$ Vậy x ∈ {$\frac{55}{12}$ } b) $\frac{1}{2}$ x – $\frac{1}{3}$ x = $\frac{1}{6}$ ⇔ x ( $\frac{1}{2}$ – $\frac{1}{3}$) = $\frac{1}{6}$ ⇔ x ( $\frac{3}{6}$ – $\frac{2}{6}$) = $\frac{1}{6}$ ⇔ x . $\frac{1}{6}$ = $\frac{1}{6}$ ⇔ x = 1 Vậy x ∈ {1} Bình luận
Đáp án: Giải thích các bước giải: 3/5x-1/4=-5/2 1/2x-1/3x=1/6 3/5x=-5/2+1/4 x×(1/2-1/3)=1/6 3/5x=-9/4 x×1/6=1/6 x=-9/4÷3/5 x=1/6÷1/6 x=-9/4×5/3 x=1 x=-15/4 vậy x=1 vậy x=-15/4 Bình luận
a) $\frac{3}{5}$ x – $\frac{1}{4}$ = $\frac{5}{2}$
⇔ $\frac{3}{5}$ x = $\frac{5}{2}$ + $\frac{1}{4}$
⇔ $\frac{3}{5}$ x = $\frac{10}{4}$ + $\frac{1}{4}$
⇔ $\frac{3}{5}$ x = $\frac{11}{4}$
⇔ x = $\frac{11}{4}$ : $\frac{3}{5}$
⇔ x = $\frac{55}{12}$
Vậy x ∈ {$\frac{55}{12}$ }
b) $\frac{1}{2}$ x – $\frac{1}{3}$ x = $\frac{1}{6}$
⇔ x ( $\frac{1}{2}$ – $\frac{1}{3}$) = $\frac{1}{6}$
⇔ x ( $\frac{3}{6}$ – $\frac{2}{6}$) = $\frac{1}{6}$
⇔ x . $\frac{1}{6}$ = $\frac{1}{6}$
⇔ x = 1
Vậy x ∈ {1}
Đáp án:
Giải thích các bước giải:
3/5x-1/4=-5/2 1/2x-1/3x=1/6
3/5x=-5/2+1/4 x×(1/2-1/3)=1/6
3/5x=-9/4 x×1/6=1/6
x=-9/4÷3/5 x=1/6÷1/6
x=-9/4×5/3 x=1
x=-15/4 vậy x=1
vậy x=-15/4