(3$\frac {1}{2}$ – 2x) : 3 $\frac{1}{3}$ = 7$\frac{1}{3}$ 07/11/2021 Bởi Kaylee (3$\frac {1}{2}$ – 2x) : 3 $\frac{1}{3}$ = 7$\frac{1}{3}$
$(3\dfrac{1}{2}-2x):3\dfrac{1}{3}=7\dfrac{1}{3} \\⇔3\dfrac{1}{2}-2x=7\dfrac{1}{3}.3\dfrac{1}{3} \\⇔\dfrac{7}{2}-2x=\dfrac{22}{3}.\dfrac{10}{3} \\⇔\dfrac{7}{2}-2x=\dfrac{220}{9} \\⇔2x=\dfrac{7}{2}-\dfrac{220}{9} \\⇔2x=\dfrac{-377}{18} \\⇔x=\dfrac{-377}{36}$ Bình luận
Đáp án: Giải thích các bước giải: (3$\dfrac{1}{2} – 2x) : 3\dfrac{1}{3} = 7\dfrac{1}{7}$ ($\dfrac{7}{2} – 2x) : \dfrac{7}{3} = \dfrac{15}{7}$ ($\dfrac{7}{2} – 2x) = \dfrac{15}{7} × \dfrac{7}{3}$ $\dfrac{7}{2} – 2x = 5$ 2x = $\dfrac{7}{2} – 5$ $2x$ $=$ $\dfrac{-3}{2}$ $x$ $=$ $\dfrac{-3}{4}$ Bình luận
$(3\dfrac{1}{2}-2x):3\dfrac{1}{3}=7\dfrac{1}{3} \\⇔3\dfrac{1}{2}-2x=7\dfrac{1}{3}.3\dfrac{1}{3} \\⇔\dfrac{7}{2}-2x=\dfrac{22}{3}.\dfrac{10}{3} \\⇔\dfrac{7}{2}-2x=\dfrac{220}{9} \\⇔2x=\dfrac{7}{2}-\dfrac{220}{9} \\⇔2x=\dfrac{-377}{18} \\⇔x=\dfrac{-377}{36}$
Đáp án:
Giải thích các bước giải:
(3$\dfrac{1}{2} – 2x) : 3\dfrac{1}{3} = 7\dfrac{1}{7}$
($\dfrac{7}{2} – 2x) : \dfrac{7}{3} = \dfrac{15}{7}$
($\dfrac{7}{2} – 2x) = \dfrac{15}{7} × \dfrac{7}{3}$
$\dfrac{7}{2} – 2x = 5$
2x = $\dfrac{7}{2} – 5$
$2x$ $=$ $\dfrac{-3}{2}$
$x$ $=$ $\dfrac{-3}{4}$