$3\frac{1}{3}x+16$ $\frac{3}{4}=-13,25$ $(3\frac{1}{2}+2x)2 $ $\frac{2}{3}=5$ $\frac{1}{3}$ $(\frac{3}{4}x+2$ $\frac{1}{2})$. $\frac{-2}{3}=$ $\frac

$3\frac{1}{3}x+16$ $\frac{3}{4}=-13,25$
$(3\frac{1}{2}+2x)2 $ $\frac{2}{3}=5$ $\frac{1}{3}$
$(\frac{3}{4}x+2$ $\frac{1}{2})$. $\frac{-2}{3}=$ $\frac{1}{8}$

0 bình luận về “$3\frac{1}{3}x+16$ $\frac{3}{4}=-13,25$ $(3\frac{1}{2}+2x)2 $ $\frac{2}{3}=5$ $\frac{1}{3}$ $(\frac{3}{4}x+2$ $\frac{1}{2})$. $\frac{-2}{3}=$ $\frac”

  1. Đáp án:

    `x = -9`

    `x = -0,75`

    `x = (-43)/12`

    Giải thích các bước giải:

    `3 1/3 x + 16 3/4 = -13,25`

    `⇒ 10/3 x + 16,75 = -13,25`

    `⇒ 10/3 x = -13,25 – 16,75`

    `⇒ 10/3 x = -30`

    `⇒ x = -30 : 10/3`

    `⇒ x = -30 . 3/10`

    `⇒ x = -9`

    .

    `(3 1/2 + 3x) 2 2/3 = 5 1/3`

    `⇒ (3,5 + 2x) . 8/3 = 16/3`

    `⇒ 3,5 + 2x = 16/3 : 8/3`

    `⇒ 3,5 + 2x = 16/3 . 3/8`

    `⇒ 3,5 + 2x = 2`

    `⇒ 2x = -1,5`

    `⇒ x = -0,75`

    .

    `(3/4 x + 2 1/2) . (-2)/3 = 1/8`

    `⇒ 3/4 x + 5/2 = 1/8 : (-2)/3`

    `⇒ 3/4 x + 5/2 = 1/8 . (-3)/2`

    `⇒ 3/4 x + 5/2 = (-3)/16`

    `⇒ 3/4 x = (-3)/16 – 5/2`

    `⇒ 3/4 x = (-3)/16 – 40/16`

    `⇒ 3/4 x = (-43)/16`

    `⇒ x = (-43)/16 : 3/4`

    `⇒ x = (-43)/16 . 4/3`

    `⇒ x = (-43)/12`

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  2. $3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25$

    $\to \dfrac{10}{3}x+\dfrac{67}{4}=\dfrac{-53}{4}$

    $\to \dfrac{10}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}$

    $\to \dfrac{10}{3}x=\dfrac{-120}{4}$

    $\to \dfrac{10}{3}x=-30$

    $\to x=-30:\dfrac{10}{3}$

    $\to x=-30.\dfrac{3}{10}$

    $\to x=-9$

    Vậy $x=-9$

    $(3\dfrac{1}{2}+2x).2\dfrac{2}{3}=5\dfrac{1}{3}$

    $\to (\dfrac{7}{2}+2x).\dfrac{8}{3}=\dfrac{16}{3}$

    $\to \dfrac{7}{2}+2x=\dfrac{16}{3}:\dfrac{8}{3}$

    $\to \dfrac{7}{2}+2x=\dfrac{16}{3}.\dfrac{3}{8}$

    $\to \dfrac{7}{2}+2x=2$

    $\to 2x=2-\dfrac{7}{2}$

    $\to 2x=\dfrac{-3}{2}$

    $\to x=\dfrac{-3}{2}:2$

    $\to x=\dfrac{-3}{4}$

    Vậy $x=\dfrac{-3}{4}$

    $(\dfrac{3}{4}x+2\dfrac{1}{2}).\dfrac{-2}{3}=\dfrac{1}{8}$

    $\to (\dfrac{3}{4}x+\dfrac{5}{2}).\dfrac{-2}{3}=\dfrac{1}{8}$

    $\to \dfrac{3}{4}x+\dfrac{5}{2}=\dfrac{1}{8}:\dfrac{-2}{3}$

    $\to \dfrac{3}{4}x+\dfrac{5}{2}=\dfrac{-3}{16}$

    $\to \dfrac{3}{4}x=\dfrac{-3}{16}-\dfrac{5}{2}$

    $\to \dfrac{3}{4}x=\dfrac{-43}{16}$

    $\to x=\dfrac{-43}{16}:\dfrac{3}{4}$

    $\to x=\dfrac{-43}{12}$

    Vậy $x=\dfrac{-43}{12}$

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