(-30/7×7/11+7/11×16/3)x5-17/3 5/39x(39/5×5/3+25/3×39/5) 07/09/2021 Bởi Maria (-30/7×7/11+7/11×16/3)x5-17/3 5/39x(39/5×5/3+25/3×39/5)
$\left ( -\dfrac{30}{7}.\dfrac{7}{11}+\dfrac{7}{11}.\dfrac{16}{3} \right ).5-\dfrac{17}{3}\\=\left ( -30.\dfrac{1}{11}+\dfrac{112}{33} \right ).5-\dfrac{17}{3}\\=\left ( -\dfrac{30}{11}+\dfrac{112}{33} \right ).5-\dfrac{17}{3}\\=\dfrac{2}{3}.5-\dfrac{17}{3}\\=\dfrac{10}{3}-\dfrac{17}{3}=-\dfrac{7}{3}\\\dfrac{5}{39}.\left ( \dfrac{39}{5}.\dfrac{5}{3}+\dfrac{25}{3}.\dfrac{39}{5} \right )\\=\dfrac{5}{39}.(13+5.13)\\=\dfrac{5}{39}.78=5.2=10$ Bình luận
`(-30/7×7/11+7/11×16/3)×5-17/3` `=7/11× (-30/7 + 16/3) ×5-17/3` `=7/11× (-90/21 + 112/21) ×5-17/3` `=7/11× 22/21 ×5-17/3` `=10/3 – 17/3` `=-7/3` `5/39×(39/5×5/3+25/3×39/5)` `=5/39 × 39/5×(5/3+25/3)` `=1×30/3` `=10.` Bình luận
$\left ( -\dfrac{30}{7}.\dfrac{7}{11}+\dfrac{7}{11}.\dfrac{16}{3} \right ).5-\dfrac{17}{3}\\=\left ( -30.\dfrac{1}{11}+\dfrac{112}{33} \right ).5-\dfrac{17}{3}\\=\left ( -\dfrac{30}{11}+\dfrac{112}{33} \right ).5-\dfrac{17}{3}\\=\dfrac{2}{3}.5-\dfrac{17}{3}\\=\dfrac{10}{3}-\dfrac{17}{3}=-\dfrac{7}{3}\\\dfrac{5}{39}.\left ( \dfrac{39}{5}.\dfrac{5}{3}+\dfrac{25}{3}.\dfrac{39}{5} \right )\\=\dfrac{5}{39}.(13+5.13)\\=\dfrac{5}{39}.78=5.2=10$
`(-30/7×7/11+7/11×16/3)×5-17/3`
`=7/11× (-30/7 + 16/3) ×5-17/3`
`=7/11× (-90/21 + 112/21) ×5-17/3`
`=7/11× 22/21 ×5-17/3`
`=10/3 – 17/3`
`=-7/3`
`5/39×(39/5×5/3+25/3×39/5)`
`=5/39 × 39/5×(5/3+25/3)`
`=1×30/3`
`=10.`