(4/7 + 3 3/5) . 4,5 + (3/7 – 2 3/5) . 4/5 06/07/2021 Bởi Emery (4/7 + 3 3/5) . 4,5 + (3/7 – 2 3/5) . 4/5
Minh sửa lại đề, nếu sai thì nói mình nha! `(4/7+3 3/5). 4/5+(3/7-2 3/5). 4/5` `=(4/7+3 3/5+3/7-2 3/5). 4/5` `=[(4/7+3/7)+(3 3/5-2 3/5)]. 4/5` `=(1+1). 4/5` `=2. 4/5` `=8/5` Bình luận
Đáp án: $\dfrac{8}{5}$ Giải thích các bước giải: $(\dfrac{4}{7}+3\dfrac{3}{5}).\dfrac{4}{5}+(\dfrac{3}{7}-2\dfrac{3}{5}).\dfrac{4}{5}$ $=\dfrac{4}{5}.(\dfrac{4}{7}+3\dfrac{3}{5}+\dfrac{3}{7}-2\dfrac{3}{5})$ $=\dfrac{4}{5}.(1+1)$ $=\dfrac{4}{5}.2$ $=\dfrac{8}{5}$ Bình luận
Minh sửa lại đề, nếu sai thì nói mình nha!
`(4/7+3 3/5). 4/5+(3/7-2 3/5). 4/5`
`=(4/7+3 3/5+3/7-2 3/5). 4/5`
`=[(4/7+3/7)+(3 3/5-2 3/5)]. 4/5`
`=(1+1). 4/5`
`=2. 4/5`
`=8/5`
Đáp án:
$\dfrac{8}{5}$
Giải thích các bước giải:
$(\dfrac{4}{7}+3\dfrac{3}{5}).\dfrac{4}{5}+(\dfrac{3}{7}-2\dfrac{3}{5}).\dfrac{4}{5}$
$=\dfrac{4}{5}.(\dfrac{4}{7}+3\dfrac{3}{5}+\dfrac{3}{7}-2\dfrac{3}{5})$
$=\dfrac{4}{5}.(1+1)$
$=\dfrac{4}{5}.2$
$=\dfrac{8}{5}$