Toán 4^n+2 + 4^n+3 + 4^n+4 +4 ^n+5 = 85 x (2^2016 : 2^2012 ) 12/07/2021 By Piper 4^n+2 + 4^n+3 + 4^n+4 +4 ^n+5 = 85 x (2^2016 : 2^2012 )
$4^{n+2}+4^{n+3}+4^{n+4}+4^{n+5}=85.(2^{2016}:2^{2012})$ $4^{n+2}.(1+4+4^2+4^3)=85.2^4$ $4^{n+2}.(1+4+16+64)=85.16$ $4^{n+2}.85=85.16$ $4^{n+2}=(85.16):85=16$ $4^{n+2}=4^2$ $n+2=2$ $→n=0$ Trả lời
Đáp án: x = 0 Giải thích các bước giải: Ta có : 4^(n + 2) + 4^(n + 3) + 4^(n + 4) + 4^(n + 5) = 85 . (2^2016 : 2^2012) => 4^n . 4^2 + 4^n. 4^3 + 4^n . 4^4 + 4^n . 4^5 = 85 . 2^4 => 4^n (4^2 + 4^3 + 4^4 + 4^5) = 85 . 2^4 => 4^n . 1360 = 85 . 16 => 4^n . 1360 = 1360 => 4^n = 1 => n = 0 Vậy n = 0 Trả lời
$4^{n+2}+4^{n+3}+4^{n+4}+4^{n+5}=85.(2^{2016}:2^{2012})$
$4^{n+2}.(1+4+4^2+4^3)=85.2^4$
$4^{n+2}.(1+4+16+64)=85.16$
$4^{n+2}.85=85.16$
$4^{n+2}=(85.16):85=16$
$4^{n+2}=4^2$
$n+2=2$
$→n=0$
Đáp án: x = 0
Giải thích các bước giải:
Ta có : 4^(n + 2) + 4^(n + 3) + 4^(n + 4) + 4^(n + 5) = 85 . (2^2016 : 2^2012)
=> 4^n . 4^2 + 4^n. 4^3 + 4^n . 4^4 + 4^n . 4^5 = 85 . 2^4
=> 4^n (4^2 + 4^3 + 4^4 + 4^5) = 85 . 2^4
=> 4^n . 1360 = 85 . 16
=> 4^n . 1360 = 1360
=> 4^n = 1
=> n = 0
Vậy n = 0