(4a+1)^2= (x-1/2)^3= (4m-3n)*(4m+3n)= (2x-y)^3= (a-3)^3= 13/08/2021 Bởi Kaylee (4a+1)^2= (x-1/2)^3= (4m-3n)*(4m+3n)= (2x-y)^3= (a-3)^3=
Đáp án: Bạn tham khảo a) `(4a+1)²=(4a)²+1²=16a²+1` b) `(x-1/2)³=x³-3.x².1/2+3.x.(1/2)²-(1/2)³=x³-3/2x²+3/4x+1/8` c) `(4m-3n)(4m+3n)=(4m)²-(3n)²=16m²-9n²` d) `(2x-y)³=(2x)³-3.(2x)².y+3.2x.y²-y³=8x³-12x²y+6xy²-y³` e) `(a-3)³=a³-3.3².a+3.3.a²-3³=a³-27a+9a²-27` Bình luận
Đáp án: Giải thích các bước giải: \((4a+1)^2=16a^2+8a+1\\ \bigg(x-\dfrac{1}{2}\bigg)^3=x^3-3.x^2.\dfrac{1}{2}+3.x.\bigg(\dfrac{1}{2}\bigg)^2+\bigg(\dfrac{1}{2}\bigg)^3=x^3-\dfrac{3}{2}x^2+\dfrac{3}{4}x-\dfrac{1}{8}\\ (4m-3n)(4m+3n)=(4m)^2-(3n)^2=16m^2-9n^2\\ (2x-y)^3=(2x)^3-3.(2x)^2.y+3.2x.y^2-y^3=8x^3-12x^2y+6xy^2-y^3\\ (a-3)^3=a^3-3.a^2.3+3.a.3^2-3^3=a^3-9a^2+27a-27\) chúc bạn học tốt! Bình luận
Đáp án: Bạn tham khảo
a) `(4a+1)²=(4a)²+1²=16a²+1`
b) `(x-1/2)³=x³-3.x².1/2+3.x.(1/2)²-(1/2)³=x³-3/2x²+3/4x+1/8`
c) `(4m-3n)(4m+3n)=(4m)²-(3n)²=16m²-9n²`
d) `(2x-y)³=(2x)³-3.(2x)².y+3.2x.y²-y³=8x³-12x²y+6xy²-y³`
e) `(a-3)³=a³-3.3².a+3.3.a²-3³=a³-27a+9a²-27`
Đáp án:
Giải thích các bước giải:
\((4a+1)^2=16a^2+8a+1\\ \bigg(x-\dfrac{1}{2}\bigg)^3=x^3-3.x^2.\dfrac{1}{2}+3.x.\bigg(\dfrac{1}{2}\bigg)^2+\bigg(\dfrac{1}{2}\bigg)^3=x^3-\dfrac{3}{2}x^2+\dfrac{3}{4}x-\dfrac{1}{8}\\ (4m-3n)(4m+3n)=(4m)^2-(3n)^2=16m^2-9n^2\\ (2x-y)^3=(2x)^3-3.(2x)^2.y+3.2x.y^2-y^3=8x^3-12x^2y+6xy^2-y^3\\ (a-3)^3=a^3-3.a^2.3+3.a.3^2-3^3=a^3-9a^2+27a-27\)
chúc bạn học tốt!