4A. a) x+1/6 = -1/2 b) x-2/10 = 3/15 c) x-7/16 = 9/24 24/10/2021 Bởi Madelyn 4A. a) x+1/6 = -1/2 b) x-2/10 = 3/15 c) x-7/16 = 9/24
$a)x+\dfrac{1}{6}=-\dfrac{1}{2}$ $x=-\dfrac{1}{2}-\dfrac{1}{6}$ $x=-\dfrac{3}{6}-\dfrac{1}{6}$ $x=-\dfrac{4}{6}$ $x=-\dfrac{2}{3}$ Vậy `x in {2/3}`. $b)x-\dfrac{2}{10}=\dfrac{3}{15}$ $x-\dfrac{1}{5}=\dfrac{1}{5}$ $x=\dfrac{1}{5}+\dfrac{1}{5}$ $x=\dfrac{2}{5}$ Vậy `x in {2/5}`. $c)x-\dfrac{7}{16}=\dfrac{9}{24}$ $x-\dfrac{7}{16}=\dfrac{6}{16}$ $x=\dfrac{6}{16}+\dfrac{7}{16}$ $x=\dfrac{13}{16}$ Vậy `x in {13/16}`. Bình luận
a, x+$\frac{1}{6}$= -$\frac{1}{2}$ ⇔ x =-$\frac{1}{2}$- $\frac{1}{6}$ ⇔ x =-$\frac{3}{6}$- $\frac{1}{6}$ ⇔ x =-$\frac{4}{6}$ ⇔ x =-$\frac{2}{3}$ vậy x ∈ {-$\frac{2}{3}$} b, x-$\frac{2}{10}$= $\frac{3}{15}$ ⇔ x-$\frac{1}{5}$ = $\frac{1}{5}$ ⇔ x =$\frac{1}{5}$ + $\frac{1}{5}$ ⇔ x =$\frac{2}{5}$ vậy x ∈ {$\frac{2}{5}$ } c, x-$\frac{7}{16}$= $\frac{9}{24}$ ⇔ x =$\frac{9}{24}$ +$\frac{7}{16}$ ⇔ x =$\frac{3}{8}$ +$\frac{7}{16}$ ⇔ x =$\frac{6}{16}$ +$\frac{7}{16}$ ⇔ x =$\frac{13}{16}$ vậy x ∈ {$\frac{13}{16}$ } Bình luận
$a)x+\dfrac{1}{6}=-\dfrac{1}{2}$
$x=-\dfrac{1}{2}-\dfrac{1}{6}$
$x=-\dfrac{3}{6}-\dfrac{1}{6}$
$x=-\dfrac{4}{6}$
$x=-\dfrac{2}{3}$
Vậy `x in {2/3}`.
$b)x-\dfrac{2}{10}=\dfrac{3}{15}$
$x-\dfrac{1}{5}=\dfrac{1}{5}$
$x=\dfrac{1}{5}+\dfrac{1}{5}$
$x=\dfrac{2}{5}$
Vậy `x in {2/5}`.
$c)x-\dfrac{7}{16}=\dfrac{9}{24}$
$x-\dfrac{7}{16}=\dfrac{6}{16}$
$x=\dfrac{6}{16}+\dfrac{7}{16}$
$x=\dfrac{13}{16}$
Vậy `x in {13/16}`.
a, x+$\frac{1}{6}$= -$\frac{1}{2}$
⇔ x =-$\frac{1}{2}$- $\frac{1}{6}$
⇔ x =-$\frac{3}{6}$- $\frac{1}{6}$
⇔ x =-$\frac{4}{6}$
⇔ x =-$\frac{2}{3}$
vậy x ∈ {-$\frac{2}{3}$}
b, x-$\frac{2}{10}$= $\frac{3}{15}$
⇔ x-$\frac{1}{5}$ = $\frac{1}{5}$
⇔ x =$\frac{1}{5}$ + $\frac{1}{5}$
⇔ x =$\frac{2}{5}$
vậy x ∈ {$\frac{2}{5}$ }
c, x-$\frac{7}{16}$= $\frac{9}{24}$
⇔ x =$\frac{9}{24}$ +$\frac{7}{16}$
⇔ x =$\frac{3}{8}$ +$\frac{7}{16}$
⇔ x =$\frac{6}{16}$ +$\frac{7}{16}$
⇔ x =$\frac{13}{16}$
vậy x ∈ {$\frac{13}{16}$ }