4A. a) x+1/6 = -1/2 b) x-2/10 = 3/15 c) x-7/16 = 9/24

4A.
a) x+1/6 = -1/2
b) x-2/10 = 3/15
c) x-7/16 = 9/24

0 bình luận về “4A. a) x+1/6 = -1/2 b) x-2/10 = 3/15 c) x-7/16 = 9/24”

  1. $a)x+\dfrac{1}{6}=-\dfrac{1}{2}$

    $x=-\dfrac{1}{2}-\dfrac{1}{6}$

    $x=-\dfrac{3}{6}-\dfrac{1}{6}$

    $x=-\dfrac{4}{6}$

    $x=-\dfrac{2}{3}$

    Vậy `x in {2/3}`.

    $b)x-\dfrac{2}{10}=\dfrac{3}{15}$

    $x-\dfrac{1}{5}=\dfrac{1}{5}$

    $x=\dfrac{1}{5}+\dfrac{1}{5}$

    $x=\dfrac{2}{5}$

    Vậy `x in {2/5}`.

    $c)x-\dfrac{7}{16}=\dfrac{9}{24}$

    $x-\dfrac{7}{16}=\dfrac{6}{16}$

    $x=\dfrac{6}{16}+\dfrac{7}{16}$

    $x=\dfrac{13}{16}$

    Vậy `x in {13/16}`.

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  2. a, x+$\frac{1}{6}$= -$\frac{1}{2}$ 

    ⇔        x     =-$\frac{1}{2}$- $\frac{1}{6}$ 

    ⇔        x =-$\frac{3}{6}$- $\frac{1}{6}$ 

    ⇔       x =-$\frac{4}{6}$

    ⇔        x =-$\frac{2}{3}$

    vậy x ∈ {-$\frac{2}{3}$}

    b, x-$\frac{2}{10}$= $\frac{3}{15}$ 

    ⇔ x-$\frac{1}{5}$ = $\frac{1}{5}$ 

    ⇔  x    =$\frac{1}{5}$ + $\frac{1}{5}$ 

    ⇔     x    =$\frac{2}{5}$ 

    vậy x ∈ {$\frac{2}{5}$ }

    c, x-$\frac{7}{16}$= $\frac{9}{24}$ 

    ⇔       x    =$\frac{9}{24}$ +$\frac{7}{16}$

    ⇔     x     =$\frac{3}{8}$ +$\frac{7}{16}$

    ⇔     x     =$\frac{6}{16}$ +$\frac{7}{16}$

    ⇔        x    =$\frac{13}{16}$

    vậy x ∈ {$\frac{13}{16}$ }

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