|x-5|-(-3)=9 135-|9-x|=35 (x+2) 5=1024 2 mũ2x-1:4=8 (x-5) (x mũ 2 -4)=0 Giúp mink vs ạ 13/11/2021 Bởi Brielle |x-5|-(-3)=9 135-|9-x|=35 (x+2) 5=1024 2 mũ2x-1:4=8 (x-5) (x mũ 2 -4)=0 Giúp mink vs ạ
Đáp án: Giải thích các bước giải: |x-5|+3=9 |x-5|=9-3 |x-5|=6 →x-5=6hoặc x-=-6 +)x-5=6 +)x-5=-6 x=6+5 x=-6+5 x=11 x=-1 vậy x∈{11;-1} 135-|9-x|=35 |9-x|=135-35 |9-x|=100 ⇒9-x=100 hoặc 9-x=-100 +)9-x=100 +) 9-x=-100 x=9-100 x=9-(-100) x=-91 x=109 vậy x∈{-91;109} (x+2).5=1024 x+2=1024:5 x+2=204,8 x=204,8-2 x=202,8 vậy x=202,8 2mũ 2x-1:4=8 2 mũ 2x-1=8.4 2 mũ 2x-1=32 2 mũ 2x-1=2 mũ 5 ⇒2x-1=5 ⇒2x=5+1 ⇒2x=6 ⇒x=6:2 ⇒x=3 vậy x=3 (x-5).(x mũ 2-4)=0 sory mình làm đc đến đây thôi Bình luận
Đáp án: `|x – 5| – (-3) = 9` `|x – 5| + 3 = 9` `|x – 5| = 9 – 3` `|x – 5| = 7` `⇔` \(\left[ \begin{array}{l}x-5=7\\x – 5 = – 7\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x= 7+5\\x = – 7+5\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x=12\\x = – 2\end{array} \right.\) Vậy `x ∈ {12 ; -2}` `135 – |9 – x| = 35` `|9 – x| = 135 – 35` `|9 – x| = 100` `⇔` \(\left[ \begin{array}{l}9-x = 100\\9-x=-100\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x = 9 – 100\\x = 9 + 100\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x= -91\\x=109\end{array} \right.\) Vậy `x ∈ {-91 ; 109}` `(x +2) . 5 = 1024` `x + 2 = 1024 : 5` `x + 2 = 204,8` `x = 204,8 – 2` `x = 202,8` Vậy `x = 202,8` `2^{2x – 1} : 4 = 8` `2^{2x – 1} = 8 . 4` `2^{2x – 1} = 32` `2^{2x – 1} = 2^5` `⇒ 2x – 1 = 5` `2x = 5 + 1` `2x = 6` `x = 6 : 2` `x = 3` Vậy `x = 3` `(x – 5) . (x^2 – 4) = 0` `⇔` \(\left[ \begin{array}{l}x – 5 = 0\\x^2 – 4 = 0\end{array} \right.\) `⇔`\(\left[ \begin{array}{l}x = 0 + 5\\x^2 = 0+4\end{array} \right.\) `⇔`\(\left[ \begin{array}{l}x = 5\\x^2 = 4\end{array} \right.\) `⇔`\(\left[ \begin{array}{l}x = 5\\x^2 = 2^2\end{array} \right.\) `⇔`\(\left[ \begin{array}{l}x = 5\\⇒x = 2\end{array} \right.\) Vậy `x ∈ {5 ; 2}` Bình luận
Đáp án:
Giải thích các bước giải:
|x-5|+3=9
|x-5|=9-3
|x-5|=6
→x-5=6hoặc x-=-6
+)x-5=6 +)x-5=-6
x=6+5 x=-6+5
x=11 x=-1
vậy x∈{11;-1}
135-|9-x|=35
|9-x|=135-35
|9-x|=100
⇒9-x=100 hoặc 9-x=-100
+)9-x=100 +) 9-x=-100
x=9-100 x=9-(-100)
x=-91 x=109
vậy x∈{-91;109}
(x+2).5=1024
x+2=1024:5
x+2=204,8
x=204,8-2
x=202,8
vậy x=202,8
2mũ 2x-1:4=8
2 mũ 2x-1=8.4
2 mũ 2x-1=32
2 mũ 2x-1=2 mũ 5
⇒2x-1=5
⇒2x=5+1
⇒2x=6
⇒x=6:2
⇒x=3
vậy x=3
(x-5).(x mũ 2-4)=0
sory mình làm đc đến đây thôi
Đáp án:
`|x – 5| – (-3) = 9`
`|x – 5| + 3 = 9`
`|x – 5| = 9 – 3`
`|x – 5| = 7`
`⇔` \(\left[ \begin{array}{l}x-5=7\\x – 5 = – 7\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x= 7+5\\x = – 7+5\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x=12\\x = – 2\end{array} \right.\)
Vậy `x ∈ {12 ; -2}`
`135 – |9 – x| = 35`
`|9 – x| = 135 – 35`
`|9 – x| = 100`
`⇔` \(\left[ \begin{array}{l}9-x = 100\\9-x=-100\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x = 9 – 100\\x = 9 + 100\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x= -91\\x=109\end{array} \right.\)
Vậy `x ∈ {-91 ; 109}`
`(x +2) . 5 = 1024`
`x + 2 = 1024 : 5`
`x + 2 = 204,8`
`x = 204,8 – 2`
`x = 202,8`
Vậy `x = 202,8`
`2^{2x – 1} : 4 = 8`
`2^{2x – 1} = 8 . 4`
`2^{2x – 1} = 32`
`2^{2x – 1} = 2^5`
`⇒ 2x – 1 = 5`
`2x = 5 + 1`
`2x = 6`
`x = 6 : 2`
`x = 3`
Vậy `x = 3`
`(x – 5) . (x^2 – 4) = 0`
`⇔` \(\left[ \begin{array}{l}x – 5 = 0\\x^2 – 4 = 0\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x = 0 + 5\\x^2 = 0+4\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x = 5\\x^2 = 4\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x = 5\\x^2 = 2^2\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x = 5\\⇒x = 2\end{array} \right.\)
Vậy `x ∈ {5 ; 2}`