Toán (1+ $\frac{8}{10}$ ).(1+ $\frac{8}{22}$ ).(1+ $\frac{8}{36}$)…(1+ $\frac{8}{8352}$ ) 16/09/2021 By Daisy (1+ $\frac{8}{10}$ ).(1+ $\frac{8}{22}$ ).(1+ $\frac{8}{36}$)…(1+ $\frac{8}{8352}$ )
Đáp án: $\dfrac{33}{4}$ Giải thích các bước giải: $\displaystyle \begin{array}{{>{\displaystyle}l}} \left( 1+\dfrac{8}{10}\right)\left( 1+\dfrac{8}{22}\right)\left( 1+\dfrac{8}{36}\right) …\left( 1+\dfrac{8}{8352}\right)\\ =\dfrac{18}{10} .\dfrac{30}{22} .\dfrac{44}{36} …\dfrac{8360}{8352}\\ =\dfrac{2.9.3.10.4.11…88.95}{1.10.2.11.3.12…87.96}\\ =\dfrac{( 2.3.4…88)( 9.10.11…95)}{( 1.2.3…87)( 10.11…96)}\\ =\dfrac{9.88}{96} =\dfrac{33}{4} \end{array}$ Trả lời
(1+8/10).1+8/22).(1+8/36)…(1+8/8352) =18.30.44…8360/10.22.36…8352 =9.2.10.3.11.4…95.88/10.11.2.12.3…96.87 =(9.10.11…95).(2.3.4…88)/(10.11.12…96).(2.3.4…87) =9.88/96 =792/96 =33/4 Bài này mik làm ở lớp rồi nha Trả lời
Đáp án:
$\dfrac{33}{4}$
Giải thích các bước giải:
$\displaystyle \begin{array}{{>{\displaystyle}l}} \left( 1+\dfrac{8}{10}\right)\left( 1+\dfrac{8}{22}\right)\left( 1+\dfrac{8}{36}\right) …\left( 1+\dfrac{8}{8352}\right)\\ =\dfrac{18}{10} .\dfrac{30}{22} .\dfrac{44}{36} …\dfrac{8360}{8352}\\ =\dfrac{2.9.3.10.4.11…88.95}{1.10.2.11.3.12…87.96}\\ =\dfrac{( 2.3.4…88)( 9.10.11…95)}{( 1.2.3…87)( 10.11…96)}\\ =\dfrac{9.88}{96} =\dfrac{33}{4} \end{array}$
(1+8/10).1+8/22).(1+8/36)…(1+8/8352)
=18.30.44…8360/10.22.36…8352
=9.2.10.3.11.4…95.88/10.11.2.12.3…96.87
=(9.10.11…95).(2.3.4…88)/(10.11.12…96).(2.3.4…87)
=9.88/96
=792/96
=33/4
Bài này mik làm ở lớp rồi nha