Toán 3. /-11/x-32=45 /x-5/=4 B.x+12/=0 /x-5/.3-(-37)=73 09/10/2021 By Jasmine 3. /-11/x-32=45 /x-5/=4 B.x+12/=0 /x-5/.3-(-37)=73
`#Dark` `|-11|.x-32=45` `⇒11x-32=45` `⇒11x=77` `⇒x=7` Vậy `x=7` `|x-5|=4` `1)x-5=4⇔x=9` `2)x-5=-4⇔x=1` Vậy `x=1` or` x=9` `x+12=0` `⇔x=-12` Vậy `x=12` `|x-5|.3-(-37)=73` `⇔3.|x-5|=73-37=36` `⇔|x-5|=36:3=12` `⇔|x-5|=12` `1)x-5=12⇔x=17` `2)x-5=-12⇔x=-7` Vậy x=17 or `x=-7` Trả lời
|-11|x-32 = 45 11 x – 32 = 45 11x = 45 + 32 11x = 77 x = 77 : 11 x = 7 |x-5| = 4 Trường hợp 1 : Trường hợp 2 : x-5=4 x-5=-4 x = 4+5 x = -4 + 5 x = 9 x = 1 Vậy x ={ 9 ; 1 } | x+ 12 | = 0 x + 12 = 0 x = 0 – 12 x = -12 |x-5| . 3 – (-37) = 73 |x-5| . 3 + 37 = 73 |x-5| . 3 =73 – 37 |x-5| . 3 = 36 |x-5| = 36 : 3 |x-5| = 12 TH1 : x-5=12 x = 12 + 5 x = 17 TH2 : x – 5 = -12 x = -12 + 5 x = -7 Trả lời
`#Dark`
`|-11|.x-32=45`
`⇒11x-32=45`
`⇒11x=77`
`⇒x=7`
Vậy `x=7`
`|x-5|=4`
`1)x-5=4⇔x=9`
`2)x-5=-4⇔x=1`
Vậy `x=1` or` x=9`
`x+12=0`
`⇔x=-12`
Vậy `x=12`
`|x-5|.3-(-37)=73`
`⇔3.|x-5|=73-37=36`
`⇔|x-5|=36:3=12`
`⇔|x-5|=12`
`1)x-5=12⇔x=17`
`2)x-5=-12⇔x=-7`
Vậy x=17 or `x=-7`
|-11|x-32 = 45
11 x – 32 = 45
11x = 45 + 32
11x = 77
x = 77 : 11
x = 7
|x-5| = 4
Trường hợp 1 : Trường hợp 2 :
x-5=4 x-5=-4
x = 4+5 x = -4 + 5
x = 9 x = 1
Vậy x ={ 9 ; 1 }
| x+ 12 | = 0
x + 12 = 0
x = 0 – 12
x = -12
|x-5| . 3 – (-37) = 73
|x-5| . 3 + 37 = 73
|x-5| . 3 =73 – 37
|x-5| . 3 = 36
|x-5| = 36 : 3
|x-5| = 12
TH1 : x-5=12
x = 12 + 5
x = 17
TH2 : x – 5 = -12
x = -12 + 5
x = -7