Toán Tìm x ∈ Z biết /x+5/=6 /2x-1/-2^2=2016^0.(-2)^2 16/10/2021 By Alice Tìm x ∈ Z biết /x+5/=6 /2x-1/-2^2=2016^0.(-2)^2
Đáp án: ↓↓ Giải thích các bước giải: `|x+5|=±6` \(\left[ \begin{array}{l}x+5=6\\x+5=-6\end{array} \right.\) \(\left[ \begin{array}{l}x=1\\x=-11\end{array} \right.\) Vậy …. `|2x-1|-2^2=2016^0.(-2)^2` `|2x-1|-2^2=1.(-2)^2` `|2x-1|-2^2=4` `|2x-1| -4 = 4 ` `|2x-1| = 4+4` `|2x-1| = ±8` \(\left[ \begin{array}{l}2x-1=8\\2x-1=-8\end{array} \right.\) \(\left[ \begin{array}{l}x=9/2\\x=-7/2\end{array} \right.\) Vậy ….. Trả lời
`|x+5|=6` `⇒`\(\left[ \begin{array}{l}x+5=6\\x+5=-6\end{array} \right.\) `⇒`\(\left[ \begin{array}{l}x=1\\x=-11\end{array} \right.\) Vậy `x∈{1,11}` `|2x-1|-2^2=2016^0.(-2)^2` `⇒|2x-1|-4=1.4` `⇒|2x-1|=4+4` `⇒|2x-1|=8` `⇒`\(\left[ \begin{array}{l}2x+1=8\\2x+1=-8\end{array} \right.\) `⇒`\(\left[ \begin{array}{l}x=\dfrac{9}{2} \\x=\dfrac{-7}{2} \end{array} \right.\) Vậy `x∈{9/2 ,(-7)/2}` Trả lời
Đáp án: ↓↓
Giải thích các bước giải:
`|x+5|=±6`
\(\left[ \begin{array}{l}x+5=6\\x+5=-6\end{array} \right.\)
\(\left[ \begin{array}{l}x=1\\x=-11\end{array} \right.\)
Vậy ….
`|2x-1|-2^2=2016^0.(-2)^2`
`|2x-1|-2^2=1.(-2)^2`
`|2x-1|-2^2=4`
`|2x-1| -4 = 4 `
`|2x-1| = 4+4`
`|2x-1| = ±8`
\(\left[ \begin{array}{l}2x-1=8\\2x-1=-8\end{array} \right.\)
\(\left[ \begin{array}{l}x=9/2\\x=-7/2\end{array} \right.\)
Vậy …..
`|x+5|=6`
`⇒`\(\left[ \begin{array}{l}x+5=6\\x+5=-6\end{array} \right.\)
`⇒`\(\left[ \begin{array}{l}x=1\\x=-11\end{array} \right.\)
Vậy `x∈{1,11}`
`|2x-1|-2^2=2016^0.(-2)^2`
`⇒|2x-1|-4=1.4`
`⇒|2x-1|=4+4`
`⇒|2x-1|=8`
`⇒`\(\left[ \begin{array}{l}2x+1=8\\2x+1=-8\end{array} \right.\)
`⇒`\(\left[ \begin{array}{l}x=\dfrac{9}{2} \\x=\dfrac{-7}{2} \end{array} \right.\)
Vậy `x∈{9/2 ,(-7)/2}`