A=1/2+1/3+…+1/2019 B=2018/1+2017/2+…+2/2017+1/2018 So sánh a/b với 1/2018 03/08/2021 Bởi Genesis A=1/2+1/3+…+1/2019 B=2018/1+2017/2+…+2/2017+1/2018 So sánh a/b với 1/2018
B = `2018 / 1 + 2017/2 + … + 2/2017 + 1/2018` ⇒ ` B = 2018 + 2017/2 + … + 2/2017 + 1/2018` ⇒ `B = 1 + (2017/2 + 1 ) + …. + (2/2017 + 1 ) + (1/2018 + 1 )` ⇒ `B = 2019/2019 + 2019/2 + …. + 2019/2017 + 2019/2018` ⇒ `B = 2019 . (1/2019 + 1/2 + … + 1/2017 + 1/2018 )` Do đó `A/B` = `(1/2+1/3+…+1/2019) / (2019 . (1/2019 + 1/2 + … + 1/2017 + 1/2018)` ⇒ `A/B = 1/2019 < 1/2018` Bình luận
B = `2018 / 1 + 2017/2 + … + 2/2017 + 1/2018`
⇒ ` B = 2018 + 2017/2 + … + 2/2017 + 1/2018`
⇒ `B = 1 + (2017/2 + 1 ) + …. + (2/2017 + 1 ) + (1/2018 + 1 )`
⇒ `B = 2019/2019 + 2019/2 + …. + 2019/2017 + 2019/2018`
⇒ `B = 2019 . (1/2019 + 1/2 + … + 1/2017 + 1/2018 )`
Do đó `A/B` = `(1/2+1/3+…+1/2019) / (2019 . (1/2019 + 1/2 + … + 1/2017 + 1/2018)`
⇒ `A/B = 1/2019 < 1/2018`