Toán a) |x|=10/13 b) |x – 5/6 | = 1/2 c) |x+4/9|- 1/2 = 3/2 28/08/2021 By Caroline a) |x|=10/13 b) |x – 5/6 | = 1/2 c) |x+4/9|- 1/2 = 3/2
Đáp án: `a)` `| x |` =`\frac{10}{13}` ⇒`x` =`\frac{10}{13}` hoặc `x` = `-\frac{10}{13}` `Vậy` `x` =`\frac{10}{13}` hoặc `x` = `-\frac{10}{13}` `b)` |`x` – `\frac{5}{6}`| = `\frac{1}{2}` ⇒ `Có` `2` `trường` `hợp ` `TH1:` `x` – `\frac{5}{6}` = `\frac{1}{2}` `x` = `\frac{1}{2}`+`\frac{5}{6}` `x` = `\frac{4}{3}` `TH2:` `x` – `\frac{5}{6}` = `-\frac{1}{2}` `x` = `-\frac{1}{2}`+ `\frac{5}{6}` `x` = `\frac{1}{3}` `Vậy` `x` =`\frac{4}{3}` hoặc `x` = `-\frac{1}{3}` c) |x + `\frac{4}{9}`| – `\frac{1}{2}` = `\frac{3}{2}` |x + `\frac{4}{9}`| = `\frac{3}{2}` + `\frac{1}{2}` |x + `\frac{4}{9}`| = `1` ⇒ `Có` `2` `trường` `hợp `: `TH1:` `x` + `\frac{4}{9}` = `1` `x` = `1` – `\frac{4}{9}` `x` = `\frac{5}{9}` `TH2:` `x` + `\frac{4}{9}` = `-1` `x` = `-1` – `\frac{4}{9}` `x` = `-\frac{13}{9}` `Vậy` `x` =`\frac{5}{9}` hoặc `x` = `-\frac{13}{9}` Trả lời
a) | x | = $\frac{10}{13}$ => x = $\frac{10}{13}$ b) | x – $\frac{5}{6}$ | = $\frac{1}{2}$ => x – $\frac{5}{6}$ = $\frac{1}{2}$ => x = $\frac{1}{2}$ + $\frac{5}{6}$ => x = 1$\frac{1}{3}$ => x – $\frac{5}{6}$ = – $\frac{1}{2}$ => x = – $\frac{1}{2}$ + $\frac{5}{6}$ = $\frac{1}{3}$ c) | x + $\frac{4}{9}$ | – $\frac{1}{2}$ = $\frac{3}{2}$ TH1: x + $\frac{4}{9}$ = $\frac{3}{2}$ + $\frac{1}{2}$ x + $\frac{4}{9}$ = 2 x = 2 – $\frac{4}{9}$ x = 1$\frac{5}{9}$ TH2: x + $\frac{4}{9}$ = – 2 x = -2 – $\frac{4}{9}$ x = -2$\frac{4}{9}$ Chúc học tốt!!! Trả lời
Đáp án:
`a)` `| x |` =`\frac{10}{13}`
⇒`x` =`\frac{10}{13}` hoặc `x` = `-\frac{10}{13}`
`Vậy` `x` =`\frac{10}{13}` hoặc `x` = `-\frac{10}{13}`
`b)` |`x` – `\frac{5}{6}`| = `\frac{1}{2}`
⇒ `Có` `2` `trường` `hợp `
`TH1:` `x` – `\frac{5}{6}` = `\frac{1}{2}`
`x` = `\frac{1}{2}`+`\frac{5}{6}`
`x` = `\frac{4}{3}`
`TH2:` `x` – `\frac{5}{6}` = `-\frac{1}{2}`
`x` = `-\frac{1}{2}`+ `\frac{5}{6}`
`x` = `\frac{1}{3}`
`Vậy` `x` =`\frac{4}{3}` hoặc `x` = `-\frac{1}{3}`
c) |x + `\frac{4}{9}`| – `\frac{1}{2}` = `\frac{3}{2}`
|x + `\frac{4}{9}`| = `\frac{3}{2}` + `\frac{1}{2}`
|x + `\frac{4}{9}`| = `1`
⇒ `Có` `2` `trường` `hợp `:
`TH1:` `x` + `\frac{4}{9}` = `1`
`x` = `1` – `\frac{4}{9}`
`x` = `\frac{5}{9}`
`TH2:` `x` + `\frac{4}{9}` = `-1`
`x` = `-1` – `\frac{4}{9}`
`x` = `-\frac{13}{9}`
`Vậy` `x` =`\frac{5}{9}` hoặc `x` = `-\frac{13}{9}`
a) | x | = $\frac{10}{13}$
=> x = $\frac{10}{13}$
b) | x – $\frac{5}{6}$ | = $\frac{1}{2}$
=> x – $\frac{5}{6}$ = $\frac{1}{2}$ => x = $\frac{1}{2}$ + $\frac{5}{6}$ => x = 1$\frac{1}{3}$
=> x – $\frac{5}{6}$ = – $\frac{1}{2}$ => x = – $\frac{1}{2}$ + $\frac{5}{6}$ = $\frac{1}{3}$
c) | x + $\frac{4}{9}$ | – $\frac{1}{2}$ = $\frac{3}{2}$
TH1: x + $\frac{4}{9}$ = $\frac{3}{2}$ + $\frac{1}{2}$
x + $\frac{4}{9}$ = 2
x = 2 – $\frac{4}{9}$
x = 1$\frac{5}{9}$
TH2: x + $\frac{4}{9}$ = – 2
x = -2 – $\frac{4}{9}$
x = -2$\frac{4}{9}$
Chúc học tốt!!!