Toán a)172 -(x+18)=93 b)x-36:18=12 c)15.x:60=32 d)2448-(5.x+148)=2000 29/07/2021 By Reagan a)172 -(x+18)=93 b)x-36:18=12 c)15.x:60=32 d)2448-(5.x+148)=2000
$a)172 -(x+18)=93$ $⇔ x+18 = 172 – 93$ $⇔ x + 18 = 79$ $⇔ x = 79 – 18$ $⇔ x = 61$ Vậy $x=61$. $b$) $x-36:18=12$ $⇔ x – 2 = 12$ $⇔ x = 12+2$ $⇔ x = 14$ Vậy $x=14$. $c$) $15.x : 60 = 32$ $⇔ 15.x= 32.60$ $⇔ 15.x = 1920$ $⇔ x = 1920 : 15$ $⇔ x = 128$ Vậy $x=128$. $d$) $d)2448-(5.x+148)=2000$ $⇔ 5x+148 = 2448-2000$ $⇔ 5x + 148 = 448$ $⇔ 5x = 448-148$ $⇔ 5x = 300$ $⇔ x = 60$ Vậy $x=60$. Trả lời
a) 172 -( $x^{}$ + 18 )=93 $x^{}$ + 18 = 172 – 93 $x^{}$ + 18 = 79 $x^{}$ = 79 – 18 $x^{}$ = 61 b) $x^{}$ – 36 : 18 = 12 $x^{}$ – 36 = 12. 18 $x^{}$ – 36 = 216 $x^{}$ = 216 + 36 $x^{}$ = 252 c) 15. $x^{}$ : 60 = 32 15. $x^{}$ = 32. 60 15. $x^{}$ = 1920 $x^{}$ = 1920 : 15 $x^{}$ = 128 d) 2448 – ( 5. $x^{}$ + 148 ) = 2000 ( 5. $x^{}$ + 148 ) = 2448 – 2000 5. $x^{}$ + 148 = 448 5. $x^{}$ = 448 – 148 5. $x^{}$ = 300 $x^{}$ = 300 : 5 $x^{}$ = 60 Trả lời
$a)172 -(x+18)=93$
$⇔ x+18 = 172 – 93$
$⇔ x + 18 = 79$
$⇔ x = 79 – 18$
$⇔ x = 61$
Vậy $x=61$.
$b$) $x-36:18=12$
$⇔ x – 2 = 12$
$⇔ x = 12+2$
$⇔ x = 14$
Vậy $x=14$.
$c$) $15.x : 60 = 32$
$⇔ 15.x= 32.60$
$⇔ 15.x = 1920$
$⇔ x = 1920 : 15$
$⇔ x = 128$
Vậy $x=128$.
$d$) $d)2448-(5.x+148)=2000$
$⇔ 5x+148 = 2448-2000$
$⇔ 5x + 148 = 448$
$⇔ 5x = 448-148$
$⇔ 5x = 300$
$⇔ x = 60$
Vậy $x=60$.
a) 172 -( $x^{}$ + 18 )=93
$x^{}$ + 18 = 172 – 93
$x^{}$ + 18 = 79
$x^{}$ = 79 – 18
$x^{}$ = 61
b) $x^{}$ – 36 : 18 = 12
$x^{}$ – 36 = 12. 18
$x^{}$ – 36 = 216
$x^{}$ = 216 + 36
$x^{}$ = 252
c) 15. $x^{}$ : 60 = 32
15. $x^{}$ = 32. 60
15. $x^{}$ = 1920
$x^{}$ = 1920 : 15
$x^{}$ = 128
d) 2448 – ( 5. $x^{}$ + 148 ) = 2000
( 5. $x^{}$ + 148 ) = 2448 – 2000
5. $x^{}$ + 148 = 448
5. $x^{}$ = 448 – 148
5. $x^{}$ = 300
$x^{}$ = 300 : 5
$x^{}$ = 60